Which two events are independent? 1.) A and X 2.) A and Y 3.) B and X 4.) B and Y

The perimeter of a rectangle is 50 ft. the length is 1 ft more than the width. what is the length and width

lesya [120]

X+1+X+1+X+X=50
4x+2=50
4x=48
X=12
Width is 12
Length is 13

6 0

3 years ago

The owner of a local nightclub has recently surveyed a random sample of n = 250 customers of the club. She would now like to det

seraphim [82]

Answer:

The required hypothesis to test is $H_0: \mu\leq 30$ and $H_1: \mu>30$ .

Step-by-step explanation:

Consider the provided information.

It is given that the nightclub has recently surveyed a random sample of n = 250 customers of the club.

She would now like to determine whether or not the mean age of her customers is over 30.

Null hypotheses is represents as $H_0$ . Thus the null hypotheses is shown as:

$H_0: \mu\leq 30$

The alternative hypotheses is represents as $H_1$ . Thus the alternative hypotheses is shown as:

$H_1: \mu>30$

Hence, the required hypothesis to test is $H_0: \mu\leq 30$ and $H_1: \mu>30$ .

8 0

3 years ago

A marketing firm would like to test-market the name of a new energy drink targeted at 18- to 29-year-olds via social media. A st

Anon25 [30]

Answer:

(a) The probability that a randomly selected U.S. adult uses social media is 0.35.

(b) The probability that a randomly selected U.S. adult is aged 18–29 is 0.22.

(c) The probability that a randomly selected U.S. adult is 18–29 and a user of social media is 0.198.

Step-by-step explanation:

Denote the events as follows:

X = an US adult who does not uses social media.

Y = an US adult between the ages 18 and 29.

Z = an US adult between the ages 30 and above.

The information provided is:

P (X) = 0.35

P (Z) = 0.78

P (Y ∪ X') = 0.672

(a)

Compute the probability that a randomly selected U.S. adult uses social media as follows:

P (US adult uses social media (X')) = 1 - P (US adult so not use social media)

$=1-P(X)\\=1-0.35\\=0.65$

Thus, the probability that a randomly selected U.S. adult uses social media is 0.35.

(b)

Compute the probability that a randomly selected U.S. adult is aged 18–29 as follows:

P (Adults between 18 - 29 (Y)) = 1 - P (Adults 30 or above)

$=1-P(Z)\\=1-0.78\\=0.22$

Thus, the probability that a randomly selected U.S. adult is aged 18–29 is 0.22.

(c)

Compute the probability that a randomly selected U.S. adult is 18–29 and a user of social media as follows:

P (Y ∩ X') = P (Y) + P (X') - P (Y ∪ X')

$=0.22+0.65-0.672\\=0.198$

Thus, the probability that a randomly selected U.S. adult is 18–29 and a user of social media is 0.198.

6 0

3 years ago

9. The ticket at right has a perimeter of 42 cm.

Liula [17]

Perimeter simply represents the sum of all side lengths of a shape. The length of the missing side of the ticket is 5 cm; the length of gold line on each ticket is 20 cm, and 2 bottles of gold ink are required to draw gold lines on 200 tickets.