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3 years ago

The wavelength of a sound in a certain material is 18 cm the frequency of a wave is 2000 Hy calculate the speed of the wave

Physics

1 answer:

Leokris [45]3 years ago

8 0

Answer:

Speed = 360m/s

Explanation:

Given the following data;

Wavelength = 18cm to meters = 18/100 = 0.18m

Frequency = 2000Hz

To find the speed;

Speed = frequency * wavelength

Speed = 2000 * 0.18

Speed = 360m/s

Therefore, the speed of the wave is 360 meters per seconds.

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Three capacitors with capacitances:

mr_godi [17]

Answer:

A. 80.0microColoumbs

B.120.0 microcoloumbs

C.37.3v

Explanation:

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4 years ago

Need help ASAP

Citrus2011 [14]

Answer:

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3 years ago

A pitcher throws a 0.144-kg baseball toward the batter so that it crosses home plate horizontally and has a speed of 42 m/s just

Solnce55 [7]

(a) 12.8 kg m/s

The impulse delivered by the bat on the baseball is equal to the change in momentum of the baseball:

$I=\Delta p = m(v-u)$

where we have

m = 0.144 kg is the mass of the ball

v = -47 m/s is the final velocity of the ball

u = 42 m/s is the initial velocity of the ball

Substituting into the equation, we find

$I=(0.144 kg)(-47 m/s-(42 m/s))=-12.8 kg m/s$

And since we are interested in the magnitude only,

$I=12.8 kg m/s$

(b) 2.78 kN

The impulse exerted on the ball is also equal to the product between the average force and the contact time:

$I=F\Delta t$

where

F is the average force exerted on the ball

$\Delta t=0.0046 s$ is the contact time

Solving the formula for F, we find

$F=\frac{I}{\Delta t}=\frac{12.8 kg m/s}{0.0046 s}=2783 N = 2.78 kN$

(c) The force exerted on the ball is much larger (1988 times more) than the weigth of the ball

The weight of the ball is given by

$W=mg$

where

m = 0.144 kg is the mass of the ball

g = 9.8 m/s^2 is the acceleration due to gravity

Solving the equation for W, we find

$W=(0.144 kg)(9.8 m/s^2)=1.4 N$

So as we see, the force exerted on the ball (2783 N) is almost 2000 times larger than the weight of the ball (1.4 N):

$\frac{F}{W}=\frac{2783 N}{1.4 N}=1988$

8 0

3 years ago

A truck goes 5 m/s to 25 in 20 seconds. What is the acceleration of the truck during 20-seconds interval?

Aliun [14]

Acceleration = (change in speed) / (time for the change)

Change in speed = (ending speed) - (starting speed)

Change in speed = (25 m/s) - (5 m/s) = 20 m/s

Time for the change = 20 sec

Acceleration = (20 m/s) / (20 sec)

<em>Acceleration = 1 m/s²</em>

4 0

3 years ago

Two point charges q and 4q are at x=0 and x=l, respectively, and free to move. a third charge is placed so that the entire three

tatuchka [14]

Explanation :

It is given that, q and 4q are placed at a distance of l.

Let x is the distance where third charge is placed so that the entire three charge system is in static equilibrium.

Equilibrium means the net force acting on the system of charges is equal to zero. Let Q is the third charge.

So, $\dfrac{kqQ}{x^2}=\dfrac{k(Q)(4q)}{(l-x)^2}$

On solving,

$x=\dfrac{l}{3}$

For magnitude :

$\dfrac{kqQ}{(l/3)^2}=\dfrac{kq4q}{l^2}$

using $x=\dfrac{l}{3}$

$Q=\dfrac{4q}{9}$

So, a charge of -4q/9 is at a distance of l/3 is placed. It is placed to the right of +q.

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4 years ago