All categories

3 years ago

1. Stephanie Schneider is running down the street at 10 m/s. She sees a double-tall latte on

Physics

2 answers:

OleMash [197]3 years ago

5 0

Stephanie's acceleration is 1 m/ $s^{2}$ .

Explanation:

In the present case, the initial velocity of the runner is given as 10 m/s. After 5 s, the runner runs with velocity of 15 m/s. If there is no change in direction, then the acceleration can be found easily as the change in velocity per unit time.

So, $Acceleration = \frac{Change in velocity}{Time}=\frac{(Final velocity -Initial velocity)}{Time}$

$Acceleration = \frac{15-10}{5}=\frac{5}{5}=1 m/s^{2}$

Thus, the acceleration will be 1 m/ $s^{2}$ .

So the change in velocity will lead to an acceleration of 1 m/ $s^{2}$ .

ra1l [238]3 years ago

5 0

Answer:15m/s-10m/s over 5s

Explanation:its a fraction the 15m/s and 10m/s are over the 5s

You might be interested in

What is the difference between tangential acceleration and centripetal acceleration?

Nuetrik [128]

Centripetal acceleration is directed along a radius so it may also be called the radial acceleration. If the speed is not constant, then there is also a tangential acceleration (at). The tangential acceleration is, indeed, tangent to the path of the particle's motion.

4 0

3 years ago

A certain first-order reaction is 58% complete in 95 s. What are the values of the rate constant and the half-life for this proc

guajiro [1.7K]

Answer:

$0.005734 s^{-1}$ and 20.86 seconds are the values of the rate constant and the half-life for this process respectively..

Explanation:

Expression for rate law for first order kinetics is given by:

$a_o=a\times e^{-kt}$

where,

k = rate constant

t = age of sample

$a_o$ = let initial amount of the reactant

a = amount left after decay process

We have :

$a_o=x$

$a=58\%\times x=0.58x$

t = 95 s

$0.58x=x\times e^{-k\times 95 s}$

$\k= 0.005734 s^{-1}$

Half life is given by for first order kinetics::

$t_{1/2}=\frac{0.693}{k}$

$=\frac{0.693}{0.005734 s^{-1}}=120.86 s$

$0.005734 s^{-1}$ and 20.86 seconds are the values of the rate constant and the half-life for this process respectively..

3 0

3 years ago

State coulombs law in word

amid [387]

<h2>state coulombs law in word</h2>

: a statement in physics: the force of attraction or repulsion acting along a straight line between two electric charges is directly proportional to the product of the charges and inversely to the square of the distance between them

hope it helps

#carry on learning

3 0

3 years ago

What is the car's speed at the bottom of the dip?The passengers in a roller coaster car feel 50% heavier thantheir true weight a

Rashid [163]

Answer:

v = 14 m/s

Explanation:

given,

radius of dip = 40 m

The passengers in a roller coaster car feel 50% heavier than their true weight.

Apparent weight

$A = W + \dfrac{W}{2}$

$A =\dfrac{3W}{2}$

$A =\dfrac{3mg}{2}$

When the car is at the bottom, the weight will be acting downwards and the centripetal force will also be acting downward where as Normal force which is apparent weight will be acting in upward direction.

now,

$N = m g + \dfrac{mv^2}{r}$