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Tomtit [17]
3 years ago
8

1. Stephanie Schneider is running down the street at 10 m/s. She sees a double-tall latte on

Physics
2 answers:
OleMash [197]3 years ago
5 0

Stephanie's acceleration is  1 m/s^{2}.

<u>Explanation:</u>

In the present case, the initial velocity of the runner is given as 10 m/s. After 5 s, the runner runs with velocity of 15 m/s. If there is no change in direction, then the acceleration can be found easily as the change in velocity per unit time.

So, Acceleration = \frac{Change in velocity}{Time}=\frac{(Final velocity -Initial velocity)}{Time}

Acceleration = \frac{15-10}{5}=\frac{5}{5}=1 m/s^{2}

Thus, the acceleration will be 1 m/s^{2}.

So the change in velocity will lead to an acceleration of 1 m/s^{2}.

ra1l [238]3 years ago
5 0

Answer:15m/s-10m/s over 5s

Explanation:its a fraction the 15m/s and 10m/s are over the 5s

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A block of mass M is attached to a spring of negligible mass and can slide on a horizontal surface along the x-direction, as sho
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Because of the frictional force, the net force will oppose direction of the block and be directed towards the left even tho the spring exerts no force at this point

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Tell the order of vessels a blood cell travels through
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4 years ago
A lighthouse is located on a small island, 3 km away from the nearest point on a straight shoreline, and its light makes four re
lbvjy [14]

Answer:

The beam of light is moving at the peed of:

\frac{dy}{dt} = \frac{80\pi}{3} km/min

Given:

Distance from the isalnd, d = 3 km

No. of revolutions per minute, n = 4

Solution:

Angular velocity, \omega = \frac{d\theta'}{dt} = 2\pi n = 2\pi \times 4 = 8\pi    (1)

Now, in the right angle in the given fig.:

tan\theta' = \frac{y}{3}

Now, differentiating both the sides w.r.t t:

\frac{dtan\theta'}{dt} = \frac{dy}{3dt}

Applying chain rule:

\frac{dtan\theta'}{d\theta'}.\frac{d\theta'}{dt} = \frac{dy}{3dt}

sec^{2}\theta'\frac{d\theta'}{dt} = \frac{dy}{3dt} = (1 + tan^{2}\theta')\frac{d\theta'}{dt}

Now, using tan\theta = \frac{1}{m} and y = 1 in the above eqn, we get:

(1 + (\frac{1}{3})^{2})\frac{d\theta'}{dt} = \frac{dy}{3dt}

Also, using eqn (1),

8\pi\frac{10}{9})\theta' = \frac{dy}{3dt}

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7 0
3 years ago
an empty boat floats in water with 10% of its volume submerged. and when it is loaded with 1200kg , the volume submerged will in
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Let volume of empty boat be = 100% = 1V

and mass of boat be M

In water 10%, 0.1V of the volume is submerged.

Mass, m of 1200kg increases the submerging from 10%, 0.1V to 70%, 0.7V

M leads to 0.1V boat submerging

boat submerging.

M + 1200kg leads to 0.7V boat submerging.

This is 60%, 0.6 V increase

By comparison

(M+1200kg) * 0.1V = 0.7V * M

0.1M + 120kg = 0.7M

120kg = 0.7M - 0.1M

120kg = 0.6M

M = (120/0.6)kg

M = 200kg.

The mass of the boat is 200kg.

4 0
2 years ago
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