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Tomtit [17]
3 years ago
8

1. Stephanie Schneider is running down the street at 10 m/s. She sees a double-tall latte on

Physics
2 answers:
OleMash [197]3 years ago
5 0

Stephanie's acceleration is  1 m/s^{2}.

<u>Explanation:</u>

In the present case, the initial velocity of the runner is given as 10 m/s. After 5 s, the runner runs with velocity of 15 m/s. If there is no change in direction, then the acceleration can be found easily as the change in velocity per unit time.

So, Acceleration = \frac{Change in velocity}{Time}=\frac{(Final velocity -Initial velocity)}{Time}

Acceleration = \frac{15-10}{5}=\frac{5}{5}=1 m/s^{2}

Thus, the acceleration will be 1 m/s^{2}.

So the change in velocity will lead to an acceleration of 1 m/s^{2}.

ra1l [238]3 years ago
5 0

Answer:15m/s-10m/s over 5s

Explanation:its a fraction the 15m/s and 10m/s are over the 5s

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Two blocks a and b ($m_a&gt;m_b$) are pushed for a certain distance along a frictionless surface. how does the magnitude of the
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Answer:

the magnitude of the work done by the two blocks is the same.

Explanation:

The work done by block a on block b is given by:

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where Fa is the force exerted by block a on block b, and d is the distance they cover.

The work done by block b on block a is given by:

W_b = F_b d

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For Newton's third law, the force exerted by block a on block b is equal to the force exerted by block b on block a, therefore

F_a = F_b

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3 years ago
A ball is spun around in circular motion such that it completes 50 rotations in 25 s.
Leokris [45]

Answer:

(A) The period of its rotation is 0.5 s (2) The frequency of its rotation is 2 Hz.

Explanation:

Given that,

a ball is spun around in circular motion such that it completes 50 rotations in 25 s.

(1). Let T be the period of its rotation. It can be calculated as follows :

T=\dfrac{25}{50}\\\\T=0.5\ s

(2). Let f be the frequency of its rotation. It can be defined as the number of rotations per unit time. So,

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3 0
3 years ago
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9966 [12]
A is the correct answer
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Convert 1erg into joule by dimensional method​
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Answer:

1 * 10^-7 [J]

Explanation:

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1 ergos [erg] is equal to 1 * 10^-7 Joules [J]

1[erg]*\frac{1*10^{-7} }{1}*[\frac{J}{erg} ] \\= 1*10^{-7}[J]

4 0
3 years ago
Assertion(A):The distance moved by an object in unit time is called its speed. Reason (R):Faster vehicles have higher speeds. i)
ikadub [295]

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it's ii) R is correct while A is incorrect

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cuz, both statements are correct but the reason is not the correct reason for the assertion,

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