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Bess [88]
2 years ago
11

PLEASE I AM BEGGING YOU WHO IS WILLING TO HELP ME I WILL GIVE BRAINLIEST IF YOU ARE WILLING TO HELP ME COMMENT DOWN BELOW

Mathematics
1 answer:
Amiraneli [1.4K]2 years ago
3 0

Answer:

I need context

Step-by-step explanation:

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What are two basic parts of a fraction
bearhunter [10]

Answer:

Numerator and denominator

Step-by-step explanation:

Numerator is the top number

Denominator is the bottom number

6 0
3 years ago
IF U CAN SOLVE THIS I LITERALLY LUV U ILL GIVE U BRAINLIEST 5 STARS AND A THANKSSS OMG PLS IN 10 MINUETSSS :c
gogolik [260]

Answer:

determination and family

7 0
3 years ago
Yuet solved the equation 6 a minus 2 b = 12 for a. Her steps are shown below. 1. Subtract 2b: 6 a = 12 minus 12 b 2. Divide by 6
Ber [7]

Question:

Yuet solved the equation 6a - 2b = 12 for a.

Her steps are shown below.

1. Subtract 2b: 6a = 12 - 2b

2. Divide by 6: a = 2 - \frac{b}{3}

Answer:

In step 1 she needed to add 2b to both sides of the equation.

Step-by-step explanation:

Given:

The above steps shows how Yuet solved an equation

Required:

True statement about Yuet's work

The implication of the statement is to state what Yuet should have done instead of what she did.

In step 1, she subtracted 2b from both sides of the equation; this is wrong.

Instead of subtracting, she ought to add 2b to both sides of the equation.

The correct steps and result is as follows:

1. Add 2b: 6a = 12 + 2b

2. Divide by 6: a = 2 + \frac{b}{3}

Hence, we can conclude that in step 1 she needed to add 2b to both sides of the equation.

4 0
3 years ago
Read 2 more answers
Someone help me with this
Jet001 [13]

2a. 14,9; 2b. 15,4; 2c. 30,8; 3. 32

For 2a., you have to set it up like this: csc 48° = 20⁄x [OR sin 48° = ˣ⁄20]. Then you would have to isolate the variable by getting rid of the denominator. The cosecant function has an extra step because you will get xcsc 48° = 20. As stated, isolate the variable; this time, divide by csc 48°. This is what 20 will be divided by to get your x, whereas the other side cancels out. Then you have to round to the nearest tenth degree.

For 2b., you have to set it up like this: sec 39° = ˣ⁄12 [OR cos 39° = 12⁄x. Then you would have to isolate the variable by getting rid of the denominator. The cosine function has an extra step because you will get xcos 39° = 12. As stated, isolate the variable; this time, divide by cos 39°. This is what 12 will be divided by to get your x, whereas the other side cancels out. Then you have to round to the nearest tenth degree.

For 2c., you have to set it up like this: cot 64° = 15⁄x [OR tan 64° = ˣ⁄15]. Then you would have to isolate the variable by getting rid of the denominator. The cotangent function has an extra step because you will get xcot 64° = 15. As stated, isolate the variable; this time, divide by cot 64°. This is what 15 will be divided by to get your x, whereas the other side cancels out. Then you have to round to the nearest tenth degree.

Now, for 3., it is unique, but similar concept. In this exercise, we are solving for an angle measure, so we have to use inverse trigonometric ratios. So, we set it up like this: cot⁻¹ 1⅗ = m<x [OR tan⁻¹ ⅝ = m<x]. We simply input this into our calculator and we get 32,00538321°. When rounded to the nearest degree, we get 32°.

WARNING: If you use a graphing calculator, you have to input it uniquely because most graphing calculators do not have the inverse trigonometric ratios programmed in their systems. This is how you would write this: tan⁻¹ 1⅗⁻¹. You set 1⅗ to the negative first power, ALONG WITH the inverse tangent function, because without it, your answer will be thrown off. Since Cotangent and Tangent are multiplicative inverses of each other, that is the reason why the negative first power is applied ALONG WITH the inverse tangent function.

**NOTE: 1⅗ = 8⁄5

Take into consideration:

sin <em>θ</em> = O\H

cos <em>θ</em><em> </em>=<em> </em>A\H

tan <em>θ</em><em> </em>= O\A

sec <em>θ</em><em> </em>= H\A

csc <em>θ</em><em> </em>= H\O

cot <em>θ</em><em> </em>= A\O

I hope this helps you out alot, but if you are still in need of assistance, do not hesitate to let me know and subscribe to my channel [username: MATHEMATICS WIZARD], and as always, I am joyous to assist anyone at any time.

7 0
3 years ago
F(x) = √3x
Nataly_w [17]

The domain of the function is (\frac{f}{g})(x) = \frac{\sqrt[3]{3x}}{5x + 2} . x \ne -\frac 25

<h3>How to determine the domain and the restrictions?</h3>

The attached image represents the complete form of the question

The functions are given as:

f(x) = \sqrt[3]{3x}

g(x) = 5x + 2

The function (f/g)(x) is calculated using:

(\frac{f}{g})(x) = \frac{f(x)}{g(x)}

This gives

(\frac{f}{g})(x) = \frac{\sqrt[3]{3x}}{5x + 2}

The denominator cannot be 0.

So, we have:

5x + 2 \ne 0

Solve for x

x \ne -\frac 25

Hence, the domain of the function is (\frac{f}{g})(x) = \frac{\sqrt[3]{3x}}{5x + 2} . x \ne -\frac 25

Read more about domain at:

brainly.com/question/1770447

#SPJ1

4 0
1 year ago
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