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kirza4 [7]
3 years ago
9

2. Jill works for Fast Food Inc. and earns $332 per week and is paid bi-weekly. How much is deducted

Mathematics
1 answer:
adoni [48]3 years ago
5 0

Answer:

Social Security: $9.63                                                                                    

Step-by-step explanation:

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Help pls i really need help
r-ruslan [8.4K]

Answer:

1 : 1

Step-by-step explanation:

First, find the unit rate of each.

Carwash : 34/4 = 8.5

So, he gets $8.5 per hour at the carwash.

Restaurant : 51/6 = 8.5

So, he gets $8.5 per hour at the resrestaurant.

The ratio is 8.5 to 8.5

Simplify it:

1:1

Hope this helps!!

7 0
3 years ago
Read 2 more answers
What is the answer to: y=-2x-5,4x+3y=15 using substitution to solve it..??
MrRa [10]

Answer:

Step-by-step explanation:

Plug the first equation into the second

4x+3(-2x-5)=15\\4x-6x-15=15\\-2x=30\\x=-15

y=-2(-15)-5

=30-5

=25

4 0
3 years ago
Use synthetic division to solve (4x^3-3x^2+5x+6) divide(x+6). What is the quotient?
NARA [144]
4 -3 5 6
-6 -24 162 -1002
-----------------------------------
4 -27 167 -996

4x^2 - 27x + 167 remainder - 996
7 0
4 years ago
Read 2 more answers
When converting units, summarize the steps using the Direct Method .
STALIN [3.7K]
Steps are simple:
1- Write the standards of conversion
2- Write the value you want to convert
3- Use cross multiplication to get the converted value

Examples:
i- Say we want to convert 890 cm to meters.
We know that 1 cm = 0.01 meters
Now, we will write the number we want to convert and use cross multiplication as follows:
1 cm     = 0.01 meters
890 cm = ?? meters
converted value = (890*0.01) / 1 = 8.9 meters

ii- Say we want to convert 568 kg to grams.
We know that 1 kg = 1000 grams
Now, we will write the number we want to convert and use cross multiplication as follows:
1 kg     = 1000 gram
568 kg = ?? grams
converted value = (568*1000) / 1 = 568000 grams

Hope this helps :)
5 0
3 years ago
Element X decays radioactively with a half life of 9 minutes. If there are 610grams of
Nookie1986 [14]

A half-life of 9 minutes corresponds to a decay factor <em>k</em> such that

\dfrac12=e^{9k}\implies k=-\dfrac19\ln\left(\dfrac12\right)

Then the time it takes for the substance to decay from 610 g to 124 g is time <em>t </em>such that

124\,\mathrm g=(610\,\mathrm g)e^{kt}

Solve for <em>t</em> :

\dfrac{62}{305}=e^{kt}

\ln\left(\dfrac{62}{305}\right)=kt

t=\dfrac1k\ln\left(\dfrac{62}{305}\right)\approx20.686

so it takes about 20.7 min for the 610 g sample to decay down to 124 g.

4 0
3 years ago
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