This problem can be solved from first principles, case by case. However, it can be solved systematically using the hypergeometric distribution, based on the characteristics of the problem:
- known number of defective and non-defective items.
- no replacement
- known number of items selected.
Let
a=number of defective items selected
A=total number of defective items
b=number of non-defective items selected
B=total number of non-defective items
Then
P(a,b)=C(A,a)C(B,b)/C(A+B,a+b)
where
C(n,r)=combination of r items selected from n,
A+B=total number of items
a+b=number of items selected
Given:
A=2
B=3
a+b=3
PMF:
P(0,3)=C(2,0)C(3,3)/C(5,3)=1*1/10=1/10
P(1,2)=C(2,1)C(3,2)/C(5,3)=2*3/10=6/10
P(2,0)=C(2,2)C(3,1)/C(5,3)=1*3/10=3/10
Check: (1+6+3)/10=1 ok
note: there are only two defectives, so the possible values of x are {0,1,2}
Therefore the
PMF:
{(0, 0.1),(1, 0.6),(2, 0.3)}
Answer:
We want to solve the equation:
(6 - 1) + (3m)i = -12 + 27i
Where m is a complex number.
first, we can rewrite this as:
5 + 3*m*i = -12 + 27*i
3*m*i = -12 - 5 + 27*i
3*m*i = -17 + 27*i
And we can write m as:
m = a + b*i
Replacing that in the above equation we get:
3*(a + b*i)*i = -17 + 27*i
3*a*i + 3*b*i^2 = -17 + 27*i
and we know that i^2 = -1
3*a*i - 3*b = -17 + 27*i
The real part in the left (-3*b) must be equal to the real part in the right (-17)
then:
-3*b = -17
b = -17/-3 = 17/3
And the imaginary part in the left (3*a) must be equal to the imaginary part in the right (27)
then:
3*a = 27
a = 27/3.
Then the value of m is:
m = a + b*i = (27/3) + (17/3)*i
Answer:
2.8 hours
Step-by-step explanation:
36.68 / 13.1 = 2.8
It’s D 69x3= 207
6% of 207 = 12.42
2% of 207 = 4.14
1% of 207 = 2.07
12.42 + 4.14 + 2.07 = 18.63
207+18.63 = 225.63
Answer:
are you fking retaxrded?
Step-by-step explanation:
