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Bas_tet [7]
2 years ago
7

Which number line shows 1 to 4 divided into fourths?

Mathematics
1 answer:
romanna [79]2 years ago
3 0

Answer:

the second one dose I believe

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PLS HELP WILL GIVE BRAINIEST these figures are congruent
geniusboy [140]

Answer:

C

Step-by-step explanation:

Answer is C, only need to move it up and to the right through translation.

3 0
2 years ago
Hey guys what is the factors of 8 (i need all of them)
satela [25.4K]

Answer:

1,2,4,8

Step-by-step explanation:

4 0
3 years ago
The equation for line r can be written as y=-1/4x+3. Line s which is parallel to lone r includes the point (-4,3). What is the e
MaRussiya [10]

Answer:

y=-\frac{1}{4}x+2

Step-by-step explanation:

Hi there!

<u>What we need to know:</u>

  • Linear equations are typically organized in slope-intercept form:y=mx+b where m is the slope and b is the y-intercept (the value of y when x is 0)
  • Parallel lines always have the same slope

<u>1) Determine the slope of line S using line R (m)</u>

y=-\frac{1}{4} x+3

We can identify clearly that the slope of the line is -\frac{1}{4}, as it is in the place of m. Because parallel lines always have the same slope, the slope of line S would also be -\frac{1}{4}. Plug this into y=mx+b:

y=-\frac{1}{4}x+b

<u>2) Determine the y-intercept of line S (b)</u>

y=-\frac{1}{4}x+b

Plug in the given point (-4,3) and solve for b

3=-\frac{1}{4}(-4)+b\\3=1+b

Subtract 1 from both sides to isolate b

3-1=1+b-1\\2=b

Therefore, the y-intercept is 2. Plug this back into y=-\frac{1}{4}x+b:

y=-\frac{1}{4}x+2

I hope this helps!

6 0
2 years ago
Dual-energy X-ray absorptiometry (DXA) is a technique for measuring bone health. One of the most common measures is total body b
sesenic [268]

Answer:

\bar d=\frac{\sum_{i=1}^n d_i}{n}=-0.001

s=\sqrt{\frac{\sum_{i=1}^n (x_i -\bar X)^2}{n-1}}=0.0095

-The sample is too small to make judgments about skewness or symmetry.

H0:\mu_{1}=\mu_{2}

H1:\mu_{1} \neq \mu_{2}

t=\frac{1.173-1.174}{\sqrt{\frac{0.1506^2}{8}+\frac{0.1495^2}{8}}}=-0.013

p_v =2*P(t_{(14)}

So the p value is a very high value and using any significance level for example \alpha=0.05, 0,1,0.15 always p_v>\alpha so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and a we don't have a significant difference between the two means.

Step-by-step explanation:

First we need to find the difference defined as:

(Operator 1 minus Operator 2)

d1=1.326-1.323=0.003      d2=1.337-1.322=0.015

d3=1.079-1.073=0.006     d4=1.229-1.233=-0.004

d5=0.936-0.934=0.002   d6=1.009-1.019=-0.01

d7=1.179-1.184=-0.005      d8=1.289-1.304=-0.015

Now we can calculate the mean of differences given by:

\bar d=\frac{\sum_{i=1}^n d_i}{n}=-0.001

And for the sample deviation we can use the following formula:

s=\sqrt{\frac{\sum_{i=1}^n (x_i -\bar X)^2}{n-1}}=0.0095

Describe the distribution of these differences using words. (which one is correct)

We can plot the distribution of the differences with the folowing code in R

differences<-c(0.003,0.015,0.006,-0.004,0.002,-0.01,-0.005,-0.015)

hist(differences)

And we got the image attached. And we can see that the distribution is right skewed but we don't have anough info to provide a conclusion with just 8 differnences.

-The sample is too small to make judgments about skewness or symmetry.

Use a significance test to examine the null hypothesis that the two operators have the same mean. Give the test statistic. (Round your answer to three decimal places.)

\bar X_{1}=1.173 represent the mean for the operator 1

\bar X_{2}=1.174 represent the mean for the operator 2

s_{1}=0.1506 represent the sample standard deviation for the operator 1

s_{2}=0.1495 represent the sample standard deviation for the operator 2

n_{1}=8 sample size for the operator 1

n_{2}=8 sample size for the operator 2

t would represent the statistic (variable of interest)

Concepts and formulas to use

We need to conduct a hypothesis in order to check if the means for the two groups are the same, the system of hypothesis would be:

H0:\mu_{1}=\mu_{2}

H1:\mu_{1} \neq \mu_{2}

If we analyze the size for the samples both are less than 30 so for this case is better apply a t test to compare means, and the statistic is given by:

t=\frac{\bar X_{1}-\bar X_{2}}{\sqrt{\frac{s^2_{1}}{n_{1}}+\frac{s^2_{2}}{n_{2}}}} (1)

t-test: Is used to compare group means. Is one of the most common tests and is used to determine whether the means of two groups are equal to each other.

Calculate the statistic

We can replace in formula (1) like this:

t=\frac{1.173-1.174}{\sqrt{\frac{0.1506^2}{8}+\frac{0.1495^2}{8}}}=-0.013

Statistical decision

For this case we don't have a significance level provided \alpha, but we can calculate the p value for this test. The first step is calculate the degrees of freedom, on this case:

df=n_{1}+n_{2}-2=8+8-2=14

Since is a bilateral test the p value would be:

p_v =2*P(t_{(14)}

So the p value is a very high value and using any significance level for example \alpha=0.05, 0,1,0.15 always p_v>\alpha so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and a we don't have a significant difference between the two means.

8 0
3 years ago
Solve - 2x - 7 &gt; X+ 8.<br> O A. x&lt;-3<br> O B. x&lt;-5<br> O C. x&gt;-5<br> O D. x&gt;-3
Rzqust [24]

Answer:

x < -5

Step-by-step explanation:

- 2x - 7 > x+ 8

Add 2x to each side

- 2x+2x - 7 > x+2x+ 8

-7 > 3x+8

Subtract 8 from each side

-7-8 > 3x+8-8

-15 > 3x

Divide by 3

-15/3 > 3x/3

-5 >x

x < -5

6 0
2 years ago
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