The domain and the range of the function are all set of real numbers
<h3>How to determine the domain and the range?</h3>
The function is given as:
f(x) = 4x + 3
The above function is a linear function
Linear functions have a domain and a range of all set of real numbers
Hence, the domain and the range of the function are all set of real numbers
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1000 mL = 1 L
0.85 L = (0.85 L)*(1000 mL/1 L) = (0.85*1000) mL = 850 mL
So, 0.85 liters is equivalent to 850 milliliters
,Answer:
I got -30
Step-by-step explanation:
Becuase when I did 5 x 2= 10
and 10 -40 = -30
The first thing we notice is that the function is reflected. So we can start by reflecting it with respect to the x-axis.
We do this by adding a negative sign in the function:

Now, we have the function reflected, but in the wrong position. We can track its position by the vertex. It was originally at (0,0) and remains at (0,0) after the reflection.
But the final function have its vertex at (-5,0), so we have to translate the function 5 units to the left. we do this by adding 5 to the x in the function:

Now, to check if there isn't any dilatation, we can check on other point in the graph to see if it checks out.
In the blue graph, we see the point (-3,-4), so let's input x = -3 and see if it checks out:

We got y = -4, so it checks out.
Thus, the answer is:
Answer:
B. [-1, ∞).
Step-by-step explanation:
g(x) = 3|x − 1| − 1
When x = 1 g(x) = 3(0) - 1 = -1.
As all negative vales of x will give positive values of |x - 1| then g(x) = -1 is its minimum value. The graph will be shaped like a letter V with the vertex at (1,-1).
Therefore the range is [-1, ∞).