Answer:
280 Cubic inches
Step-by-step explanation:
When finding the volume, the equation is V=l*w*h
Therefore, the equation should be:
10.1*3.9*6.8
This is equal to exactly 267.852
However, the answer is 280 cubic in. because it's a larger number and it's about 13 from the actual answer. On the other hand, 250 cubic in. is about 17 from the actual number.
Answer:

Step-by-step explanation:
Given:
To find:
- Summation notation of the given series
Summation Notation:

Where n is the number of terms and
is general term.
First, determine what kind of series it is, there are two main series that everyone should know:
A series that has common difference.
A series that has common ratio.
If you notice and keep subtracting the next term with previous term:
Two common difference, we can in fact say that the series is arithmetic one. Since we know the type of series, we have to find the number of terms.
Now that brings us to arithmetic sequence, we know that first term is 5 and last term is 251, we’ll be finding both general term and number of term using arithmetic sequence:
<u>Arithmetic Sequence</u>

Where
is the nth term,
is the first term and
is the common difference:
So for our general term:

And for number of terms, substitute
= 251 and solve for n:

Now we can convert the series to summation notation as given the formula above, substitute as we get:

Answer:
Snickerdoodles are 0.22$ each and chocolate chip are 0.43$ each
Step-by-step explanation:
using the information in the problem, you can make 2 separate equations: 8x+12y=6.92 and 5x+5y=3.25, let x= the cost of a snickerdoodle and y= the cost of a chocolate chip cookie.
With the 2 equations, we can isolate the y variable of the first equation and simplify which will give us y= -2/3x +6.92/12.
You can now take that equation and plug it into equation number 2:
5x+5(-2/3x + 6.92/12)=3.25.
solve that equation by multiplying 5 through the brackets: 5x-10/3x+34.6/12=3.25
add common terms: 5/3x=4.4/12
find the value of x, you will get x=0.22
plug the value of x (0.22) into one of your equations and solve for the y-value