Answer:
Angle BOC = 28; Angle AOB = 21
Step-by-step explanation:
Because angle AOC = AOB + BOC you can set the equation:
2x+10 + 4x-15 = 49
<solve for x>
6x - 5 = 49
6x = 54
x= 9
<plug in x for the angles>
BOC = 2(9) +10 = 28
AOB = 4(9) - 15 = 21
Answer:
84 is the highest possible course average
Step-by-step explanation:
Total number of examinations = 5
Average = sum of scores in each examination/total number of examinations
Let the score for the last examination be x.
Average = (66+78+94+83+x)/5 = y
5y = 321+x
x = 5y -321
If y = 6, x = 5×6 -321 =-291.the student cannot score -291
If y = 80, x = 5×80 -321 =79.he can still score higher
If If y = 84, x = 5×84 -321 =99.This would be the highest possible course average after the last examination.
If y= 100
The average cannot be 100 as student cannot score 179(maximum score is 100)
Answer:
x = 2sqrt(5)
Step-by-step explanation:
We can use the Pythagorean theorem to solve
The legs are x and 8/2 =4
and the hypotenuse is 6
a^2 + b^2 = c^2
x^2 +4^2 = 6^2
x^2 +16 = 36
Subtract 16 from each side
x^2 +16-16=36-16
x^2 = 20
Take the square root of each side
sqrt(x^2) = sqrt(20)
x = sqrt(4*5)
x = sqrt(4) sqrt(5)
x = 2sqrt(5)
Answer:
2.83
Step-by-step explanation:
d= Square root of (x2 - x1 )^2 +( y2- y1)^2
from the point given you
x1= -6
y1 = -17
x2 = -8
y2 = -19
by applying the formula
Square root of ( -8 - (-6))^2 + ( -19 - (-17))^2
Square root of (-8+6) + (-19+17)^2
