Answer:
If 9x is not =27, then x is not =3
Step-by-step explanation:
Going out on a limb here, please ignore if I'm missing it:
If 9x is not =27, then x is not =3
(I can't type the equal sign with a slash through it.)
Answer:
b= $3.99×2 + $2.50= $10.48
Step-by-step explanation:
We have the following unknowns:
p: number of people in the club
f: ounces of fruit punch
c: ounces of cheese
b: budget in dollars
We know that
p=12
Priya is preparing 8 ounces of fruit punch per person, so:
f= 8×p = 8×12 = 96
We need 96 ounces of fruit punch
Priya is preparing 2 ounces of cheese per person, so:
c= 2×p = 2×12 = 24
We need 24 ounces of cheese
A package of cheese contains 16 ounces and costs $3.99. In order to get all the cheese we need, Priya have to buy 2 packages of cheese.
2×16=32
32>24
A one-gallon jug of fruit punch contains 128 ounces and costs $2.50. Then, Priya have to buy only one gallon jug.
128>96
The budget would be:
b= $3.99×2 + $2.50×1
Answer:
Soleil and Malvin would have $ 5,000 all together after 13 days.
Step-by-step explanation:
Since Soleil and Malvin each work a job, and Soleil starts with $ 700 and makes $ 100 per day while Malvin starts out with $ 200 and makes $ 120 per day, to determine after how many days will they have at least $ 5000 all together it must be done the following calculation:
5,000 - 700 - 200 = 4,100
200X + 120X = 4,100
320X = 4,100
X = 4,100 / 320
X = 12.8
So Soleil and Malvin would have $ 5,000 all together after 13 days.
Consider a homogeneous machine of four linear equations in five unknowns are all multiples of 1 non-0 solution. Objective is to give an explanation for the gadget have an answer for each viable preference of constants on the proper facets of the equations.
Yes, it's miles true.
Consider the machine as Ax = 0. in which A is 4x5 matrix.
From given dim Nul A=1. Since, the rank theorem states that
The dimensions of the column space and the row space of a mxn matrix A are equal. This not unusual size, the rank of matrix A, additionally equals the number of pivot positions in A and satisfies the equation
rank A+ dim NulA = n
dim NulA =n- rank A
Rank A = 5 - dim Nul A
Rank A = 4
Thus, the measurement of dim Col A = rank A = five
And since Col A is a subspace of R^4, Col A = R^4.
So, every vector b in R^4 also in Col A, and Ax = b, has an answer for all b. Hence, the structures have an answer for every viable preference of constants on the right aspects of the equations.
