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3 years ago

8

The right rectangular prism is packed with unit cubes of the appropriate unit fraction edge length find the volume of the right

rectangular prism in centimeters

1 answer:

evablogger [386]3 years ago

5 0

Answer:

try base time height as that is the way to find the volume and then whatever measurements it is so if it is meters then divide from 100 etc..

Step-by-step explanation:

You might be interested in

faltersainse [42]

Answer:

The probability that a ship that is declared defecive is sound is 0.375

Step-by-step explanation:

Let P(A|B) denote the conditional probability of A given B. We will make use of the equation

P(A|B) = P(A) × P(B|A) / P(B)

We have the probabilities:

P(Declared Defective (detected) | Defective) = 0.95

P(not Detected | Defective) = 1-0.95=0.05

P(Declared Sound | Sound) = 0.97

P(Declared Defective |Sound) = 1-0.97=0.03

P(Defective)=0.05

P(Sound)= 1- 0.05 = 0.95

We can calculate:

P(Declared Defective)= P(Detected | Defective)×P(Defective) + P(Declared Defective |Sound) ×P(Sound) = 0.95×0.05 + 0.03×0.95=0.076

P(S | Declared Defective) =

(P(Sound) × P(Declared Defective | Sound)) / P(Declared Defective)

=0.95×0.03 /0.076 =0.375

3 0

3 years ago

Plz give full reasoning

disa [49]

Answer:

r = 12

Step-by-step explanation:

DG + GM = DM , substitute values

r + 3 + 4r - 28 = 35 , that is

5r - 25 = 35 ( add 25 to both sides )

5r = 60 ( divide both sides by 5 )

r = 12

4 0

2 years ago

Read 2 more answers

At 12:00 AM (hour 0 of the day) the tide at a certain beach was at its lowest level of the day: 1.0 feet. At 6:00PM (hour 18 of

tankabanditka [31]

Answer:

<h2>At noon the tide will be at the lowest point which is 1 ft </h2>

Step-by-step explanation:

please see attached a sketch of the solution for your reference

What is a sinusoidal wave?

Alternatively called a sine wave is a type of wave that shows a repetitive pattern or oscillation, it normally starts from a low point moves to the next point which is usually higher than the previous and repeats itself as the whole process continues

5 0

3 years ago

You are given the following equation.

saul85 [17]

Answer:

Step-by-step explanation:

Given the equation 4x²+ 49y² = 196

a) Differentiating implicitly with respect to y, we have;

$8x + 98y\frac{dy}{dx} = 0\\98y\frac{dy}{dx} = -8x\\49y\frac{dy}{dx} = -4x\\\frac{dy}{dx} = \frac{-4x}{49y}$

b) To solve the equation explicitly for y and differentiate to get dy/dx in terms of x,

First let is make y the subject of the formula from the equation;

If 4x²+ 49y² = 196

49y² = 196 - 4x²

$y^{2} = \frac{196}{49} - \frac{4x^{2} }{49} \\y = \sqrt{\frac{196}{49} - \frac{4x^{2} }{49} \\} \\$

Differentiating y with respect to x using the chain rule;

Let $u= \frac{196}{49} - \frac{4x^{2} }{49}$

$y = \sqrt{u} \\y =u^{1/2} \\$

$\frac{dy}{dx} = \frac{dy}{du} * \frac{du}{dx}$

$\frac{dy}{du} = \frac{1}{2}u^{-1/2} \\$

$\frac{du}{dx} = 0 - \frac{8x}{49} \\\frac{du}{dx} =\frac{-8x}{49} \\\frac{dy}{dx} = \frac{1}{2} ( \frac{196}{49} - \frac{4x^{2} }{49})^{-1/2} * \frac{-8x}{49}\\\frac{dy}{dx} = \frac{1}{2} ( \frac{196-4x^{2} }{49})^{-1/2} * \frac{-8x}{49}\\\frac{dy}{dx} = \frac{1}{2} ( \sqrt{ \frac{49}{196-4x^{2} })} * \frac{-8x}{49}\\\frac{dy}{dx} = \frac{1}{2} *{ \frac{7}\sqrt {196-4x^{2} }} * \frac{-8x}{49}\\$

$\frac{dy}{dx} = \frac{-4x}{7\sqrt{196-4x^{2} } }$

c) From the solution of the implicit differentiation in (a)

$\frac{dy}{dx} = \frac{-4x}{49y}$

Substituting $y = \sqrt{\frac{196}{49} - \frac{4x^{2} }{49} \\$ into the equation to confirm the answer of (b) can be shown as follows

$\frac{dy}{dx} = \frac{-4x}{49\sqrt{\frac{196-4x^{2} }{49} } }\\\frac{dy}{dx} = \frac{-4x}{49\sqrt{196-4x^{2}}/7} }\\\\\frac{dy}{dx} = \frac{-4x}{7\sqrt{196-4x^{2}}}$

This shows that the answer in a and b are consistent.

6 0

3 years ago

tenemos $5000 en una cuenta. A final de cada mes se ingresa un 5% del dinero que hay en la cuenta en dicho momento. Calcular el

LiRa [457]

Al final del primer mes tenemos:

5000 + 5000*0.05 = 5250

Al final del segundo mes:

5250 + 5250*0.05 = 5512.5

Y al final del tercer mes nos queda:

5512.5 + 5512.5*0.05 = 5788.125

El dinero que habra en la cuent despues de un trimestre es $5788.125

Para calcular en que porcentaje ha subido la cantidad inicial, dividimos la cantidad extra obtenida despues de un trimestre entre la cantidad inicial:

$\begin{gathered} \frac{788.125}{5000}=0.157625 \\ \text{Expresado en porcentaje:} \\ 0.157625\cdot100=15.7625 \end{gathered}$

Ha subido en un 15.7625%

6 0

1 year ago