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kompoz [17]
3 years ago
5

A triangle ABC is reflected across the y-axis and then translated 5 units down to triangle A'B'C'. How are the side lengths of t

riangle ABC related to the side lengths of triangle A'B'C'?

Mathematics
1 answer:
Oksi-84 [34.3K]3 years ago
3 0

Answer:

d, c, a, b

d= 32, 56

c = 34, 64

a = 85, 92

b = 23, 55

Step-by-step explanation:

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malfutka [58]

Answer:

Hello some parts of your question is missing below is the missing part

answer : A) p-value =  0.0019 ,

The level of significance ( 0.05 ) > p-value ( 0.0019 )

B) There is no dependence between the two ratings

Step-by-step explanation:

A) using a 0.05 level of significance and test for independence of the quality of management

Test statistic : X^{2}  ∑ ( Oi - Ei )^2 / Ei

= [(40-35)^2 / 35 ] +  [(25-24.5)^2 / 24.5 ] +  [(5-10.5)^2 / 10.5]  +  [(35-40)^2 / 40]  +  [(35-28)^2 / 28]  +  [(10-12)^2 / 12]  +   [ (25-25)^2 / 25 ]  +  [(10-17.5)^2 / 17.5 ]  + [(15-7.5)^2 / 7.5]  =  17.03  

p-value = 0.0019

Df = 4  ,

The level of significance ( 0.05 ) > p-value ( 0.0019 )

B) There is no dependence between the two ratings

4 0
3 years ago
Assume that the flask shown in the diagram can be modeled as a combination of a sphere and a cylinder. Based on this assumption,
kompoz [17]

If the flask shown in the diagram can be modeled as a combination of a sphere and a cylinder, then its volume is

V_{flask}=V_{sphere}+V_{cylinder}.

Use following formulas to determine volumes of sphere and cylinder:

V_{sphere}=\dfrac{4}{3}\pi R^3,\\ \\V_{cylinder}=\pi r^2h,

wher R is sphere's radius, r - radius of cylinder's base and h - height of cylinder.

Then

  • V_{sphere}=\dfrac{4}{3}\pi R^3=\dfrac{4}{3}\pi \left(\dfrac{4.5}{2}\right)^3=\dfrac{4}{3}\pi \left(\dfrac{9}{4}\right)^3=\dfrac{243\pi}{16}\approx 47.71;
  • V_{cylinder}=\pi r^2h=\pi \cdot \left(\dfrac{1}{2}\right)^2\cdot 3=\dfrac{3\pi}{4}\approx 2.36;
  • V_{flask}=V_{sphere}+V_{cylinder}\approx 47.71+2.36=50.07.

Answer 1: correct choice is C.

If both the sphere and the cylinder are dilated by a scale factor of 2, then all dimensions of the sphere and the cylinder are dilated by a scale factor of 2. So

R'=2R, r'=2r, h'=2h.

Write the new fask volume:

V_{\text{new flask}}=V_{\text{new sphere}}+V_{\text{new cylinder}}=\dfrac{4}{3}\pi R'^3+\pi r'^2h'=\dfrac{4}{3}\pi (2R)^3+\pi (2r)^2\cdot 2h=\dfrac{4}{3}\pi 8R^3+\pi \cdot 4r^2\cdot 2h=8\left(\dfrac{4}{3}\pi R^3+\pi r^2h\right)=8V_{flask}.

Then

\dfrac{V_{\text{new flask}}}{V_{\text{flask}}} =\dfrac{8}{1}=8.

Answer 2: correct choice is D.


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