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bezimeni [28]
3 years ago
7

Helppp 11 pointssss pleaseee

Mathematics
1 answer:
Yuri [45]3 years ago
4 0

Answer:

n = 9.8 cm

r = 7..1 cm

this is the answer

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I just need help on confirming my answers please.
-Dominant- [34]
Both A. and D. are increasing.
8 0
3 years ago
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What is the ratio of 364:78
Klio2033 [76]
You'd want to simplify that by dividing both terms by the greatest common factor which is the product of the shared primes of both numbers prime factorization...

364=2*2*7*13, 78=2*3*13, so the GCF is 2*13=26, now divide both terms by 26

14:3
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3 years ago
Jing makes a cut through a block of butter, as shown. What are the
levacccp [35]

Answer: C) 4 x 3 cm

Step-by-step explanation:

The only dimension affected by the cut was 5, because the cut was perfectly parallel to the 4x3 face.

6 0
3 years ago
Lori buys a $400 certificate deposit that earns 1.8% interest compounded monthly how much will a cd be worth in six years
Firlakuza [10]

Answer:

$1445.11

Step-by-step explanation:

The formula to use would be:

F=P(1+r)^t

Where

F is the future amount (what we want to find)

P is the present (principal) amount (this is 400)

r is the rate of interest, monthly (1.8% or 0.018)

t is the time in months (6 years = 6 * 12 = 72)

Now substituting, we get:

F=P(1+r)^t\\F=400(1+0.018)^{72}\\F = 400(1.018)^{72}\\F=1445.11

After 6 years, the CD will be worth $1445.11

8 0
4 years ago
In the figure below, mZ1=(x +48) and m2 2=2xº.<br> Find the angle measures.
NARA [144]
Since m < 1 and m < 2 are complementary angles wherein the measure of their angles add up to 90°, we can establish the following equation:

m < 1 + m < 2 = 90°
x° + 48° + 2x° = 90°

Combine like terms:
48° + 3x° = 90°

Subtract 48° from both sides:

48° - 48° + 3x° = 90° - 48°

3x = 42°

Divide both sides by 3 to solve for x:

3x/3 = 42/3

x = 14°

Plug in the value of x into the equation to fins m< 1 and m < 2:

m < 1 + m < 2 = 90°
(14° + 48°) + 2(14)° = 90°
62° + 28° = 90°

90° = 90° (True statement)

Therefore:

m < 1 = 62°
m < 2 = 28°
6 0
3 years ago
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