b= 63 and that is your answer
Answer:
1. b ∈ B 2. ∀ a ∈ N; 2a ∈ Z 3. N ⊂ Z ⊂ Q ⊂ R 4. J ≤ J⁻¹ : J ∈ Z⁻
Step-by-step explanation:
1. Let b be the number and B be the set, so mathematically, it is written as
b ∈ B.
2. Let a be an element of natural number N and 2a be an even number. Since 2a is in the set of integers Z, we write
∀ a ∈ N; 2a ∈ Z
3. Let N represent the set of natural numbers, Z represent the set of integers, Q represent the set of rational numbers, and R represent the set of rational numbers.
Since each set is a subset of the latter set, we write
N ⊂ Z ⊂ Q ⊂ R .
4. Let J be the negative integer which is an element if negative integers. Let the set of negative integers be represented by Z⁻. Since J is less than or equal to its inverse, we write
J ≤ J⁻¹ : J ∈ Z⁻
Answer:
(b) 1.7 in
Step-by-step explanation:
The area of a regular polygon in terms of perimeter and apothem is given by the formula ...
A = 1/2Pa
For a hexagon, the perimeter is 6 times the side length, so this becomes ...
A = 1/2(6s)a = 3sa . . . . . for side length 's' and apothem 'a'
__
Solving for the apothem, we find ...
a = A/(3s)
For the given values of area and side length the apothem is ...
a = 10.4/(3·2) = 1.733... ≈ 1.7 . . . inches
The apothem, rounded to tenths, is 1.7 inches.
Answer:
p = -6.5
Step-by-step explanation:
<u>Given:</u>
<u>Solving for p:</u>
- 18+ 2 (3p – 8) = –37
- 18 + 6p - 16 = -37
- 6p + 2 = -37
- 6p = -37 - 2
- 6p = -39
- p = -39/6
- p = -6.5
Option 2 is correct in the list
