Question

Find the value of b. B² = 256

Answer 1

$B^2=256$

$\mathrm{For\:}x^2=f\left(a\right)\mathrm{\:the\:solutions\:are\:}x=\sqrt{f\left(a\right)},\:\:-\sqrt{f\left(a\right)}$

$B=\sqrt{256},\:B=-\sqrt{256}$

$\sqrt{256}$

$\mathrm{Factor\:the\:number:\:}\:256=16^2$

$=\sqrt{16^2}$

$=16$

$-\sqrt{256} =-16$

$B=16,\:B=-16$

Hope I helped you!

Success!

by a random romanian guy