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In-s [12.5K]
3 years ago
14

If a(x) = 3x + 1 and p(x)= x-4, what is the domain of (b•a)(x)?

Mathematics
1 answer:
Sedbober [7]3 years ago
7 0

Answer:

  all real numbers

Step-by-step explanation:

Both a(x) and b(x) are polynomials. The set of polynomials is closed on multiplication, so (b•a)(x) will also be a polynomial. <em>All</em> polynomials are defined for <em>all real numbers</em>. The domain is the set of input values (x) for which the function is defined.

The domain of (b•a)(x) is all real numbers.

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Please help me with acellus
Bezzdna [24]

Answer:

66

Step-by-step explanation:

angle 1 and 4 are supplementary so the 2 added together equal 180. 180-124=56.

The sum of the triangles angles equal 180

180-56-58=66 which is the value of angle 2

5 0
2 years ago
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Alyssa is paid a 5 percent commission on her total sales each month. Last month, she sold $30,000 worth of items. After a state
grigory [225]
$1,365 is the answer, (the third choice)
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2 years ago
a craftsman drill is on sale for $99.99. If the sales tax rate is 7%, how much will molly have to pay for the drill?
Nadya [2.5K]
99.99 x (7%/100)= 6.9993
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Hope this helped.
8 0
3 years ago
Someone help with this
elena-14-01-66 [18.8K]

The quadrants are I, II, III, and IV, (meaning 1, 2, 3, and 4). The first quadrant is in the upper right, which has both positive x and positive y values. The second quadrant is the upper left, which has negative x and positive y values. The third quadrant is the lower left, which has both negative x and y values. The fourth quadrant is the lower right, which has positive x and negative y values. Using this knowledge and our positive and negative signs, the following are the answers to questions 1-6.

1) (-4, -2) - Quadrant III, both x and y are negative

2) (0, -7) - This point is actually on the y-axis. The x value is 0 and the y value is -7, so the graph is 7 units down from the origin on the y-axis.

3) (0,0) - This point is the origin, or where the x and y axes cross (the middle of the graph).

4) (6, -9) - This point is in Quadrant IV, because it has a positive x value and a negative y value

5) (3,5) - This point is in Quadrant I, because both the x and y values are positive.

6) (8,0) - This point is on the x-axis. The y-value is zero, so this point is 8 units to the right of the origin between Quadrant I and Quadrant IV.

Using the knowledge presented above, to graph the points given to you in the second part of the problem, first you can figure out what quadrant or part of the graph the point is on. Then, you can count the number of units (squares on the graph) in the right direction (remember that up is positive on the y-axis and down is negative, and to the right is positive on the x-axis and to the left is negative) in order to plot the points. Then, you must connect the points that correspond to the same figure in order to create the figures.

Please comment if you have any questions!

Hope this helps!

7 0
3 years ago
A classroom has a presentation system that consists of four components, each of which must activate if the system is to work ade
Vikki [24]

Answer:

0.87

Step-by-step explanation:

According to the scenario, computation of given data are as follows,

As, each must be activated, this shows that components are in series.

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So, overall system reliability  = 0.97 × 0.99 × 0.97 × 0.93

overall system reliability = 0.866 or 0.87

8 0
3 years ago
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