Select the correct answer.
1 answer:
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Answer:
see graph
Step-by-step explanation:
g(x) = 3^ x .
h(x) = 2^-x
We want to subtract them
f(x) = 3^x - 2^(-x)
I will rewrite without the negative exponent
f(x) = 3^x - (1/2)^(x)
Lets pick a couple of points
f(0) = 3^0 - (1/2) ^ 0 = 1-1 = 0
As x gets large 3^x gets large and 1/2^x gets close to 0, so it will get large
As x goes to negative infinity, 3^x goes to zero and 1/2^ gets large so we get - infinitity
This can be solved by factoring.
First, set the expression equal to zero.
Then, find two the factors of
whose sum is 
.
Split into these two factors.
Next, factor by grouping.
By the Zero Product Property, set each factor equal to zero.
These are the solutions. The Complex Conjugate Root Theorem and the Fundamental Theorem of Algebra both state that, in essence, real and imaginary solutions come in pairs of two and every polynomial of degree
has exactly complex roots, but real roots are also complex roots. That sounds confusing, but this just means that you're done. Your answers are -2 and 1/3. There are two real roots.
First, set the expression equal to zero.
Then, find two the factors of
Split
Next, factor by grouping.
By the Zero Product Property, set each factor equal to zero.
These are the solutions. The Complex Conjugate Root Theorem and the Fundamental Theorem of Algebra both state that, in essence, real and imaginary solutions come in pairs of two and every polynomial of degree