Question

192=6000(.02(8/5-4Y)+.08y) solve for y

Answer 1

Given:

The equation is:

$192=6000\left(0.02\left(\dfrac{8}{5}-4y\right)+0.08y\right)$

To find:

The value of y.

Solution:

We have,

$192=6000\left(0.02\left(\dfrac{8}{5}-4y\right)+0.08y\right)$

On simplification, we get

$192=6000\left(0.02\times 1.6-0.02\times 4y+0.08y\right)$

$192=6000\left(0.032-0.08y+0.08y\right)$

$192=6000\left(0.032\right)$

$192=192$

Since LHS=RHS and the equation is free from the variable y, therefore the given equation is true for all real values of y.

Hence, all real values of y are solutions.