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vivado [14]
3 years ago
14

Please help solve,

Mathematics
2 answers:
Dvinal [7]3 years ago
5 0
Idk but this ain’t it
ANEK [815]3 years ago
4 0

Answer:

Number of guests: 8, 12, 20, 56, 40

Number of tables:  2, 3, 5, 7, 5

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X = 42 and y = - 23 are the two numbers
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The coeffiecient for 6m + 7 is<br> m
Over [174]

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The coefficient of 6m is 6

Step-by-step explanation:

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Find the slope of the line below. *
earnstyle [38]

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I believe it would be -3,4.

Step-by-step explanation:

To find slope you use rise over run, where you count up first, then go to the side. If you count down on the left you count 3 boxes, but since its going down its negative. And to get the run you count over 4. Meaning it's -3,4

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-(4t^2-5t-6)<br> How to factor it?
swat32
How to factor it?
<span>-(4t^2-5t-6)
</span>=
-(t-2)(4t+3)

Try Mathway .com
8 0
3 years ago
Consider the initial value problem for the function y given by:
alex41 [277]

Answer:

Step-by-step explanation:

a.

An implicit expression is a relation of the form y = f(x) where f is a a function with x as a variable.

\frac{\mathrm{d} y}{\mathrm{d} t}=2y\left ( 1-\frac{y}{4} \right )\\\frac{\mathrm{d} y}{\mathrm{d} t}=\frac{y}{2}(4-y)

On integrating both sides, we get

\int \frac{dy}{y(4-y)}=\int \frac{1}{2}\,dt\\\frac{1}{4}\int \frac{1}{y}+\frac{1}{4-y}\,dy=\frac{1}{2}\,dt\\

We know that \int \frac{dy}{y}=\ln y.

Therefore,

\int \frac{dy}{y(4-y)}=\int \frac{1}{2}\,dt\\\frac{1}{4}\int \frac{1}{y}+\frac{1}{4-y}\,dy=\int \frac{1}{2}\,dt\\\frac{1}{4}\left [ \ln y-\ln (4-y) \right ] =\frac{t}{2}+C

As y(0)=1,

C=-\frac{\ln 3}{4}

So, \frac{1}{4}\left [ \ln y-\ln (4-y) \right ] =\frac{t}{2}-\frac{\ln 3}{4}

b.

\frac{1}{4}\left [ \ln y-\ln (4-y) \right ] =\frac{t}{2}-\frac{\ln 3}{4}\\\ln y-\ln (4-y)=2t-\ln 3\\\ln \left ( \frac{y}{4-y} \right )=2t-\ln 3\\\frac{y}{4-y}=e^{2t-\ln 3}\\y=(4-y)e^{2t-\ln 3}\\y\left ( 1+e^{2t-\ln 3}\\ \right )=4e^{2t-\ln 3}\\y=\frac{4e^{2t-\ln 3}}{1+e^{2t-\ln 3}}

3 0
4 years ago
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