Answer:
Simplifying a square root just means factoring out any perfect squares from the radicand, moving them to the left of the radical symbol, and leaving the other factor inside the radical symbol. If the number is a perfect square, then the radical sign will disappear once you write down its root.
(2t^2−t−8)(2t^2+2t−1)
= (2t^2+−t+−8)(2t^2+2t+−1)
= (2t^2)(2t^2) + (2t^2)(2t) + (2t^2)(−1) + (−t)(2t^2) + (−t)(2t) + (−t)(−1) + (−8)(2t^2) + (−8)(2t) + (−8)(−1)
=4t^4+4t^3−2t^2−2t^3−2t^2+t−16t^2−16t+8
=4t^4+2t^3−20t^2−15t+8
Sorry if I made it too complicated
Answer:
1. Group C; 2. Group B; 3. Group D; 4. Group A
Step-by-step explanation:
These equations are in the form
, where v₀ is the initial velocity and h₀ is the initial height.
The first equation has no value for v₀ and a value of 19 for h₀. This means there is no velocity, so the ball is dropped, and since the initial height is 19, it is dropped from 19 meters. This makes it group C.
The second equation has a value of 50 for v₀ and no value for h₀. This means the initial velocity is 50 and there is no initial height. This makes it group B.
The third equation has no value for v₀ and a value of 50 for h₀. This means there is no initial velocity, so the ball is being dropped, and the initial height is 50. This makes it group D.
The fourth equation has a value of 19 for v₀ and no value for h₀. This means the initial velocity is 19 and there is no initial height. This makes it group A.
5y + 3 > -7 y + 13
Subtract 3 from both sides
5y > -7y + 13 - 3
Add 7y to both sides
5y + 7y > 13 - 3
12y > 10
Divide by 12, which is positive so the sign doesn't flip
y > 10/12 = 5/6
Answer: y > 5/6