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luda_lava [24]
3 years ago
5

Find area of blue shaded region

Mathematics
1 answer:
RUDIKE [14]3 years ago
8 0

Answer:

\approx \: 7.33 \:  {cm}^{2}

Step-by-step explanation:

Area of the blue shaded region

=  \frac{ \theta}{360 \degree}  \times \pi r_1^2  - \frac{ \theta}{360 \degree}  \times \pi r_2^2  \\  \\  =   \frac{ \pi\theta}{360 \degree} ( r_1^2 - r_2^2) \\  \\ ( r_1 = 4 \: cm, \:  \:  r_2 = 3\: cm, \:  \:  \theta = 120 \degree) \\  \\ =   \frac{ 3.14 \times 120 \degree}{360 \degree} ( 4^2 - 3^2) \\  \\  =   \frac{ 3.14 }{3}  \times 7 \\  \\  =  \frac{21.98}{3}  \\  \\  = 7.32666667 \\  \\  \approx \: 7.33 \:  {cm}^{2}

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Step-by-step explanation:

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3 years ago
How do I solve out 5x188
mihalych1998 [28]

Answer:

940

Step-by-step explanation:

 188

<u>×    5</u>

 940

--------------------------------------------------------

8 * 5 = 40

Carry the 4 to the next 8

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Add the 4 to the 40

40 + 4 = 48

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1 * 5 = 5

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*Hope this helps .^.*

5 0
3 years ago
The total resistance in a circuit with two parallel resistors is 2 ohms and R1 is 6 ohms. Using the equation for R2, in terms of
ivanzaharov [21]
<h2>Answer:</h2>

R_2  is 3 ohms

<h2>Step-by-step explanation:</h2>

In a circuit containing two resistors R_1 and R_2 connected together in parallel, the total resistance R_T is given by;

\frac{1}{R_T} = \frac{1}{R_1}  + \frac{1}{R_2}              ---------(i)

<em>Make </em>R_2<em> subject of the formula;</em>

=> \frac{1}{R_2} = \frac{1}{R_T}  - \frac{1}{R_1}  

=> \frac{1}{R_2} = \frac{R_1 - R_T}{R_TR_1}

=>   {R_2} = \frac{R_TR_1}{R_1 - R_T}       ---------------(ii)

From the question,

R_1 = 6Ω

R_T = 2Ω

Substitute these values into equation (ii) as follows;

=> {R_2} = \frac{2*6}{6 - 2}

{R_2} = \frac{12}{4}

R_2 = 3Ω

Therefore, the value of R_2 = 3 ohms or R_2 = 3Ω

3 0
3 years ago
For brainiest:):):):):):):)
exis [7]
I used 3.14 for pi to solve easier.

6. 6.28

7. 21.98

8. 94.2
6 0
3 years ago
Center (-15,11) radius 2
kodGreya [7K]

Answer:

(x+15)^2+(y-11)^2=4

Step-by-step explanation:

<u><em>The question is</em></u>

How do you write an equation for a circle with center (-15,11) and radius 2?

we know that

The equation of a circle in center radius form is given by

(x-h)^2+(y-k)^2=r^2

where

(h,k) is the center of the circle

r is the radius of the circle

substitute the given vales

(x+15)^2+(y-11)^2=2^2

(x+15)^2+(y-11)^2=4

8 0
3 years ago
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