Problem: 7/10 - 1/2
1/2 = x/10 Find the common denominator
1/2 = 5/10
Subtract the numerators
7-5
Answer: 2/10
Simplest form: 1/5
First, you divide 4 by 2 before you subtract them by 5 using BODMAS, or BIDMAS.
4 ÷ 2 = 2
5 - 2 = 3
3 is your answer
★ Arithmetic Progression [ Explicit and Recursive notation ] ★
Arithmetic Sequence - 19 , 9 , -1 ...
Recursive Notation -
First term = 19
Common difference = -10
In subscript notation - [ a₁ = 19 , aₙ = aₙ-₁ -10 ]
In functional notation - f(n) = f (n -1) -10
Explicit Notation - f ( n ) = f ( 1 ) + d ( n - 1 )
= 19 - 10 ( n -1 )
= 29 - 10n
It's functional and subscript notations resides the same
Answer:
The number of houses built in Town B is 56.
Step-by-step explanation:
We are given that in 2010, the number of houses built in Town A was 25 percent greater than the number of houses built in Town B.
Also, 70 houses were built in Town A during 210.
Let the number of houses built in Town B be 'x'.
So, according to the question;
Number of houses built in Town A = Number of houses built in Town B + 25% of the houses built in Town B
x = 56
Hence, the number of houses built in Town B is 56.
Part 1: 4 quarts in a gallon
4 * 5 = 20 quarts
Part 2: 20 * 2 = 40
They will make $40.00
