All categories

3 years ago

Find x if h(x)=-2 Please Helppp :) ill mark brainliest

Mathematics

2 answers:

Paladinen [302]3 years ago

7 0

Answer:

x=4

Step-by-step explanation:

hope this helps:)

Viefleur [7K]3 years ago

4 0

Answer:

x = -6

Step-by-step explanation:

For this problem, we will use the general expression given by OP in the comments as h(x) = 12 / x to find the value of x that makes this evaluation true, h(x) = -2.

For this, we will simply set the two expressions equal to each other, since they both are h(x), and solve for x.

h(x) = 12 / x

h(x) = -2

h(x) = h(x)

12/x = -2

12/x * x = -2 * x

12 = -2x

12 * (-1/2) = -2x * (-1/2)

-6 = x

Hence, the value of x that makes h(x) = -2, is x = -6.

Cheers.

You might be interested in

PLEASE HELP AND EXPLAIN!!

prisoha [69]

Answer:

Step-by-step explanation:

This isnt a cartisean coordinate plane so A is wrong. One of our points is at

$- 3 + i$

Because it coincide with real number 3, and negative imaginary number i.

Conjugates are terms with opposite inverse of terms.

So our conjugates is

$- 3 - i$

3 0

3 years ago

What is 47 times 23 ?

Arte-miy333 [17]

Answer:

1081

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

PLS HELP QUICK! <br> LINKS WILL BE REPORTED....

Semenov [28]

I think it’s dababy I’m not sure

8 0

3 years ago

Suppose that E(θˆ1) = E(θˆ2) = θ, V(θˆ 1) = σ2 1 , and V(θˆ2) = σ2 2 . Consider the estimator θˆ 3 = aθˆ 1 + (1 − a)θˆ 2. a Show

katen-ka-za [31]

Answer:

Step-by-step explanation:

Given that:

$E( \hat \theta _1) = \theta \ \ \ \ E( \hat \theta _2) = \theta \ \ \ \ V( \hat \theta _1) = \sigma_1^2 \ \ \ \ V(\hat \theta_2) = \sigma_2^2$

If we are to consider the estimator $\hat \theta _3 = a \hat \theta_1 + (1-a) \hat \theta_2$

a. Then, for $\hat \theta_3$ to be an unbiased estimator ; Then:

$E ( \hat \theta_3) = E ( a \hat \theta_1+ (1-a) \hat \theta_2)$

$E ( \hat \theta_3) = aE ( \theta_1) + (1-a) E ( \hat \theta_2)$

$E ( \hat \theta_3) = a \theta + (1-a) \theta = \theta$

b) If $\hat \theta _1 \ \ and \ \ \hat \theta_2$ are independent

$V(\hat \theta _3) = V (a \hat \theta_1+ (1-a) \hat \theta_2)$

$V(\hat \theta _3) = a ^2 V ( \hat \theta_1) + (1-a)^2 V ( \hat \theta_2)$

Thus; in order to minimize the variance of $\hat \theta_3$ ; then constant a can be determined as :

$V( \hat \theta_3) = a^2 \sigma_1^2 + (1-a)^2 \sigma^2_2$

Using differentiation:

$\dfrac{d}{da}(V \ \hat \theta_3) = 0 \implies 2a \ \sigma_1^2 + 2(1-a)(-1) \sigma_2^2 = 0$

⇒

$a (\sigma_1^2 + \sigma_2^2) = \sigma^2_2$

$\hat a = \dfrac{\sigma^2_2}{\sigma^2_1+\sigma^2_2}$

This implies that

$\dfrac{d}{da}(V \ \hat \theta_3)|_{a = \hat a} = 2 \ \sigma_1^2 + 2 \ \sigma_2^2 > 0$

So, $V( \hat \theta_3)$ is minimum when $\hat a = \dfrac{\sigma_2^2}{\sigma_1^2+\sigma_2^2}$

As such; $a = \dfrac{1}{2}$ if $\sigma_1^2 \ \ = \ \ \sigma_2^2$

4 0

4 years ago

Write the following phrase as an algebraic expression. Use k for the unknown.

Advocard [28]

Answer: 20k

Step-by-step explanation: product means to multiply. Use k for the unknown number. 20 times k can be written as 20k.

3 0

3 years ago