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3 years ago

Simplify the expression and write without negative exponents

Mathematics

1 answer:

mr_godi [17]3 years ago

8 0

$( \frac{ - 5 {x}^{2} {y}^{ - 1} }{1} ) {}^{4} = (\frac{ - 5 {x}^{2} }{y} ) {}^{4} = \frac{ - 625 {x}^{6} }{ {y}^{4} }$

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Find parametric equations through point P=(2,2,7) in the direction of the vector v = (44, 14, -20)?

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Answer:

(x, y, z) = (2+44t, 2+14t, 7-20t)

Step-by-step explanation:

One way to write parametric equations for line L is ...

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(x, y, z) = (2+44t, 2+14t, 7-20t)

If you like, you can remove a common factor of 2 from the coefficients of t.

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2 years ago

Find the length of the leg. If your answer is not an integer, leave it in simplest radical<br> form

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Step-by-step explanation:

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2 years ago

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<h2>Answer and Explanation to questions 13,14,15</h2>

13) $\mathbf{\overline{XY}\cong\overline{CD}}$ as given in the question.

14) $\mathbf{\overline{XY}\cong\overline{YZ}}$ Since Y is the midpoint of XZ. So, Y will divide XZ in equal halves into XY and YZ.

15) $\mathbf{\overline{CD}\cong\overline{YZ}}$

$\because\overline{\textrm{XY}}\cong\overline{\textrm{CD}}$ and $\overline{\textrm{XY}}\cong\overline{\textrm{YZ}}$ . So, $\overline{\textrm{CD}}\cong\overline{\textrm{YZ}}$

<h2>Answer and Explanation to questions 16,17,18</h2>

∠3 is supplementary to ∠1 means: ∠3 + ∠1 = 180°

And, according to figure ∠1 + ∠2 = 180° as ∠1 and ∠2 form a straight line.

∠3 + ∠1 = 180° .............(i)

∠1 + ∠2 = 180° .............(ii)

subtracting equation (i) and (ii) will give ∠3 = ∠2 ..........(iii)

15) ∠3 is supplementary to ∠1 as given in the question

16) ∠2 is supplementary to ∠1 as shown be equation (ii)

18) ∠3 ≅ ∠2 as shown by equation (iii)

<h2>Answer and Explanation to questions 19</h2>

∠3 and ∠4 form a straight line. Therefore, ∠3 + ∠4 = 180° .......(i)

∠4 and ∠5 form a straight line. Therefore, ∠4 + ∠5 = 180° .......(ii)

subtracting equation (i) and (ii)

∠3 + ∠4 - (∠4 + ∠5) = 180°-(180°)

∠3 + ∠4 - ∠4 - ∠5 = 180°-180°

∠3 - ∠5 = 0

∴ ∠3 = ∠5 (Hence Proved)

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2 years ago