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3 years ago

8

PLZ HELP ME DO THIS ITS DUE RN

1 answer:

Ostrovityanka [42]3 years ago

8 0

Answer:

least to greatest: -5 and 1

Step-by-step explanation:

they represent the zeroes of the function and are sorted from least to greatest

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The first term of an arithmetic sequence is 7 and the sixth term is 22. Find(a)the common difference;(2)(b)the twelfth term;(2)(

SVEN [57.7K]

d = 3 , a₁₂ = 40 and S $x_{100}$ = 7775

In an arithmetic sequence the nth term and sum to n terms are

<h3>• a $n$ = a₁ + (n-1)d</h3><h3>• S $_n$ = $\frac{n}{2}$ [2a + (n-1)d]</h3><h3>where d is the common difference</h3><h3>a₆ = a₁ + 5d = 22 ⇒ 7 + 5d = 22 ⇒ 5d = 15 ⇔ d = 3</h3><h3>a₁₂ = 7 + 11d = 7 +( 11× 3) = 7 + 33 = 40</h3><h3>S₁₀₀ = $\frac{50}{2}$ [(2×7) +(99×3)</h3><h3> = 25(14 + 297) = 25(311)= 7775</h3>

7 0

3 years ago

B) Solve<br> (i)<br> 9x = 36

Vaselesa [24]

Answer:

4

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

A certain number is the same as the square root of the product of 8 and the number find the number

Rudik [331]

So, we have x=√8x. The square root is a number times itself, so x=√x*x. That means that 8 is x.

6 0

3 years ago

Don't be childish I will report thanks

Semenov [28]

Answer:

what do you mean childish?.. anyway your answer is

-2| 3 - 6 |

= -6

happy to help!

5 0

2 years ago

Read 2 more answers

Consider the expression √(√625).

const2013 [10]

Answer:

5

Step-by-step explanation:

Square Root - Finding a number that multiplies itself twice into the number within the square root

With this meaning, we need to find a number that multiplies itself into 625.

Finding calculations using exponents will help,

25^2 is equal to 625. Therefore $\sqrt{25}$

We are not finished, as there is another square root right after, empowering the parenthesis, so what number multiplies itself equals 25?

This would be 5, therefore $\sqrt{(\sqrt{625}) }$ is equal to 5.

6 0

3 years ago