Simplify the expression below as much as possible.
2 answers:
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Answer with Step-by-step explanation:
We are given that two independent tosses of a fair coin.
Sample space={HH,HT,TH,TT}
We have to find that A, B and C are pairwise independent.
According to question
A={HH,HT}
B={HH,TH}
C={TT,HH}
{HH}
={HH}
={HH}
P(E)=
Using the formula
Then, we get
Total number of cases=4
Number of favorable cases to event A=2
Number of favorable cases to event B=2
Number of favorable cases to event C=2
If the two events A and B are independent then
Therefore, A and B are independent
Therefore, B and C are independent
Therefore, A and C are independent.
Hence, A, B and C are pairwise independent.