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kakasveta [241]
2 years ago
12

The graph of function g (x) predicts the profit of jimmy's famous Jer*y for a week. The x-axis represents the number of employee

s earning overtime for the week. The y-axis is the business's profit for the week in hundreds of dollars.

Mathematics
1 answer:
Rashid [163]2 years ago
5 0

By identifying the maximums, we see that in each blank we need to write:

1) 2

2) 2

3) greater.

<h3>How to complete the given statement?</h3>

First, we need to find the maximum of the function g(x).

You can see that for x = 2 we have the maximum of the parabola, which gives y = 9.

Then the maximum profit is got when 2 employees earn overtime.

We also need to find the maximum for the table. Notice that the maximum value of the table also happens for x = 2, and this time the maximum is y = 16.

So we can see that the maximum of Cathy's cupcakes is larger than the maximum of Jimmy's.

If you want to learn more about maximums:

brainly.com/question/19819849

#SPJ1

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How do I name the intersection of two planes?
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Well, the interseciton of 2 planes would be a line, so it would be like line AB when it goes through the 2 points A and B
4 0
3 years ago
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Pls help and show workings
andreev551 [17]

Answer: x = 11

Step-by-step explanation:

same as the last question, set them as equal and solve. here's my work:

<em>5x - 1 = 4x + 10</em>

<em>5x - 1 (+ 1) = 4x + 10 (+ 1)</em>

<em>5x = 4x + 11</em>

<em>5x (- 4x) = 4x (- 4x) + 11</em>

x = 11

8 0
3 years ago
Jamie is conducting inventory at a public library, so they have to verify that each item from the catalog is in its correct loca
Andrei [34K]

Answer:

Mean: 33.3

SD: 32.8

Step-by-step explanation:

4 0
3 years ago
Use lagrange multipliers to find the point on the plane x â 2y + 3z = 6 that is closest to the point (0, 2, 4).
Arisa [49]
The distance between a point (x,y,z) on the given plane and the point (0, 2, 4) is

\sqrt{f(x,y,z)}=\sqrt{x^2+(y-2)^2+(z-4)^2}

but since \sqrt{f(x,y,z)} and f(x,y,z) share critical points, we can instead consider the problem of optimizing f(x,y,z) subject to x-2y+3z=6.

The Lagrangian is

L(x,y,z,\lambda)=x^2+(y-2)^2+(z-4)^2+\lambda(x-2y+3z-6)

with partial derivatives (set equal to 0)

L_x=2x+\lambda=0\implies x=-\dfrac\lambda2
L_y=2(y-2)-2\lambda=0\implies y=2+\lambda
L_z=2(z-4)+3\lambda=0\implies z=4-\dfrac{3\lambda}2
L_\lambda=x-2y+3z-6=0\implies x-2y+3z=6

Solve for \lambda:

x-2y+3z=-\dfrac\lambda2-2(2+\lambda)+3\left(4-\dfrac{3\lambda}2\right)=6
\implies2=7\lambda\implies\lambda=\dfrac27

which gives the critical point

x=-\dfrac17,y=\dfrac{16}7,z=\dfrac{25}7

We can confirm that this is a minimum by checking the Hessian matrix of f(x,y,z):

\mathbf H(x,y,z)=\begin{bmatrix}f_{xx}&f_{xy}&f_{xz}\\f_{yx}&f_{yy}&f_{yz}\\f_{zx}&f_{zy}&f_{zz}\end{bmatrix}=\begin{bmatrix}2&0&0\\0&2&0\\0&0&2\end{bmatrix}

\mathbf H is positive definite (we see its determinant and the determinants of its leading principal minors are positive), which indicates that there is a minimum at this critical point.

At this point, we get a distance from (0, 2, 4) of

\sqrt{f\left(-\dfrac17,\dfrac{16}7,\dfrac{25}7\right)}=\sqrt{\dfrac27}
8 0
3 years ago
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