Answer:
0.018 is the probability that a randomly selected college student has an IQ greater than 131.5
Step-by-step explanation:
We are given the following information in the question:
Mean, μ = 100
Standard Deviation, σ = 15
We are given that the distribution of IQ score is a bell shaped distribution that is a normal distribution.
Formula:
a) P(IQ greater than 131.5)
P(x > 131.5)
Calculation the value from standard normal z table, we have,
0.018 is the probability that a randomly selected adult has an IQ greater than 131.5
Answer:529
Step-by-step explanation:23x23= 529 since length times width equals the area
Answer:
Please who knows the full question to this problem am unable to see the full question.....
Volume varies 1/P.
V=K/P.
21=K/1.
K=21.
The relation is V=21/P.
....if P=0.7 and K=21.
and the relation to solve the question is V=21/P then put the value of P in the formula which will be...
V=21/0.7.
V=30m^3.
This is my answer..i hope it helps
Answer:
25/216
Step-by-step explanation:
P( 6) = number of 6's / total number of outcomes
=1/6
Then roll again
factor of 12: 1,2,3,4,6,12 =
1,2,3,4,6 are possible rolls = 5
P ( factor of 12)=number of numbers that are factor of 12 / total number of outcomes = 5/6
Then roll again
P( number less than 6) = numbers less than 6 / total
=5/6
P (6, factors of 12, number less than 6) = 1/6*5/6 *5/6
=25/216
Answer:
-1
Step-by-step explanation:
x+4/4 = 9/12
If you plug in -1, then 3/4=9/12.
This is a true proportion.
Hope this helps!!! PLZ MARK BRAINLIEST!!!
