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anyanavicka [17]
3 years ago
15

Assume that college students have IQ scores that are normally distributed with a mean of 100 and a standard deviation of 15. Fin

d the probability that a randomly selected college student has an IQ greater than 115.5. Group of answer choices
Mathematics
1 answer:
jolli1 [7]3 years ago
3 0

Answer:

0.018 is  the probability that a randomly selected college student has an IQ greater than 131.5                                

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 100

Standard Deviation, σ = 15

We are given that the distribution of IQ score is a bell shaped distribution that is a normal distribution.

Formula:

a) P(IQ greater than 131.5)

P(x > 131.5)

Calculation the value from standard normal z table, we have,  

0.018 is  the probability that a randomly selected adult has an IQ greater than 131.5

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Show Your Work<br> Please help I’ll mark brainliest
fgiga [73]

Answer:

(c)

Step-by-step explanation:

3+2+4 = 9,  4+2= 6- 3= 3

3 0
3 years ago
Haley works at a candy store. There are 10 types of bulk candy. Find the probability that one type of candy will be chosen more
DIA [1.3K]

Answer:

Probability that one type of candy will be chosen more than once in 10 trials = 0.2639

Step-by-step explanation:

This is a binomial experiment because

- A binomial experiment is one in which the probability of success doesn't change with every run or number of trials.

- It usually consists of a number of runs/trials with only two possible outcomes, a success or a failure. (10 trials, with the outcome of each trial being that we get the required candy or not)

- The outcome of each trial/run of a binomial experiment is independent of one another.

Binomial distribution function is represented by

P(X = x) = ⁿCₓ pˣ qⁿ⁻ˣ

n = total number of sample spaces = 10 trials

x = Number of successes required = number of times we want to pick a particular brand of candy = more than once, that is > 1

p = probability of success = probability of picking a particular brand of candy from a bulk with 10 different types of candies = (1/10) = 0.10

q = probability of failure = Probability of not picking our wanted candy = 1 - p = 1 - 0.1 = 0.90

P(X > 1) = 1 - P(X ≤ 1)

P(X ≤ 1) = P(X = 0) + P(X = 1)

P(X = 0) = ¹⁰C₀ (0.10)⁰ (0.90)¹⁰⁻⁰ = 0.3486784401

P(X = 1) = ¹⁰C₁ (0.10)¹ (0.90)¹⁰⁻¹ = 0.387420489

P(X ≤ 1) = 0.3486784401 + 0.387420489 = 0.7360989291

P(X > 1) = 1 - 0.7360989291 = 0.2639010709 = 0.2639

Hope this Helps!!!

5 0
3 years ago
Can you find the volume of this cylinder for me please??
Morgarella [4.7K]

Answer:

37.7 inches

Step-by-step explanation:

V=πr^2h

Is the formula for the volume of a cylinder

^2 is exponent 2

r is the radius (2) and h is the height (3)

6 0
2 years ago
Read 2 more answers
Last month a car dealership sold 80 cats. Of all cars sold 15% of them were red how many cars that were sold were red
telo118 [61]

Answer:

12

Step-by-step explanation:

Multiply 80 by .15

5 0
2 years ago
Read 2 more answers
If a spring is oscillating (moving) according to the velocity equation v(t) = 2sin(t) (in ft/s), then what is its displacement o
Feliz [49]

ANSWER

4 ft

EXPLANATION

The velocity equation of the oscillating spring is given by the function.

v(t)=2  \sin(t)   \:  \:  {ms}^{ - 1}

To find the displacement function, we need to to Integrate the velocity function.

s(t) = \int \: 2 \sin(t) dt

s(t) =  -  2 \cos(t)  + k

At time t=0, there was no displacement.

This implies that,

s(0) = 0

0=  -  2 \cos(0)  + k

0=  -  2 + k

k = 2

The displacement function then becomes,

s(t) =  -  2 \cos(t)  + 2

To find the displacement over the first π seconds, we put

t = \pi

into the equation for the displacement to get,

s(\pi) =  -  2 \cos(\pi)  + 2

s(\pi) =  -  2 ( - 1)  + 2

s(\pi) =  2  + 2 =4 ft

7 0
3 years ago
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