Sin(kx)=0=>x=0,π,...
∫0πsin(kx)dx=−1/kcos(kx)|π0=−1/k(cos(kπ)−cos(k∗0))
if k is odd then,=−1/k(−1−1)=−1/k(−2)=2/k
if k is even then,=−1/k(1−1)=0
Answer: The 25th term of the sequence is 75
Step-by-step explanation:
The given sequence depicts an arithmetic progression. The consecutive terms differ by a common difference. We will apply the formula for arithmetic progression.
Tn = a + (n-1)d
Tn = The value of the nth term of the arithmetic sequence.
a = first term of the sequence.
d = common difference (difference between a term and the consecutive term behind it)
n = number of terms in the sequence.
From the information given,
a = 3
d = 5-3 = 7-5 = 2
We want to look for the 25th term, T25
So n = 25
T25 = 3 + (25-1)2 = 3+ 24×2
T25 = 3 + 72 = 75
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Use cos sin and tan and looks up rules of cos sin tan and it will show you the rules and use those methods to plug into your equation
Answer:
9
Step-by-step explanation:
6+x, when x = 3
6+(3)
6+3=9
