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never [62]
3 years ago
10

He starts from school, which is at the location indicated by the point on the grid above. He then walks to the library 5 units w

est. After the library, he goes to the gym, which is 6 units north. From the gym, he goes to his guitar class, which is 3 units west. Which of the following is the location of his guitar class?
Mathematics
2 answers:
Usimov [2.4K]3 years ago
5 0
3 units to the west because if you add the 3 and the 6 it’s the west
Charra [1.4K]3 years ago
4 0

Answer:

So, David's guitar class is located at point (-6,2) on the coordinate grid.

Step-by-step explanation:

David starts from school, which is two units to the right and four units down from the origin. This location is indicated by the point (2,-4).

He walks 5 units west to the library.

So, find the point that is 5 units to the west of point (2,-4). Distances east and west on the grid represent a change in the x-coordinate. Moving 5 units to the west on the grid from point (2,-4) places the new location at point (-3,-4).

He then walks 6 units north to the gym.

So, find the point that is 6 units to the north of point (-3,-4). Distances north and south on the grid represent a change in the y-coordinate. Moving 6 units to the north on the grid from point (-3,-4) places the new location at point (-3,2).

David then walks 3 units west to his guitar class.

So, find the point that is 3 units to the west of point (-3,2). Moving 3 units to the west on the grid from point (-3,2) places the new location at point (-6,2).

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Answer:

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Step-by-step explanation:

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4 0
3 years ago
A local gym instructor has a course load that allows her to teach eight classes. At an interest meeting, 8 people wanted high-­‐
cricket20 [7]

Answer:

<u>The final curse load of the local gym instructor is this:</u>

<u>High-­‐impact aerobics = 1</u>

<u>Low-­‐impact aerobics =  4</u>

<u>Jazzercise = 1</u>

<u>Step exercise = 2</u>

Step-by-step explanation:

1. Let's apportion the class load using the Hamilton method

Number of classes the local gym instructor can teach = 8

Total number of students that want to take a class = 114 (8 people wanted high-­‐impact aerobics, 64 wanted low-­‐impact aerobics, 11 wanted jazzercise, and 31 wanted step exercise)

Standard divisor = 114/8 = 14.25

Now, we can apportion the students in in Standard quotas, this way:

High-­‐impact aerobics = 8/14.25 = 0.5614

Low-­‐impact aerobics = 64/14.25 = 4.49

Jazzercise = 11/14.25 = 0.7719

Step exercise = 31/14.25 = 2.1754

Now, we find the Minimum quota, just considering the whole number and don't taking into account the decimals, this way:

High-­‐impact aerobics = 0

Low-­‐impact aerobics =  4

Jazzercise = 0

Step exercise = 2

As we can see we have 6 classes and there are 2 still pending. Those 2 goes to the classes with the highest decimal portion, in this case, Jazzercise .7719 and High-­‐impact aerobics with .5614.

<u>The final course load is this:</u>

<u>High-­‐impact aerobics = 1</u>

<u>Low-­‐impact aerobics =  4</u>

<u>Jazzercise = 1</u>

<u>Step exercise = 2</u>

7 0
3 years ago
Sally is planning a trip for 225 students
Gala2k [10]

Answer: 75 students.

Step-by-step explanation:

In the data set we have a total of 10 + 8 + 7 + 5 = 30 students.

of those, 10 want to go to the park, the percentage is:

(10/30)*100% = 33.3%

Then, out of the 225, we can expect that a 33.3% (or 0.333 in decimal form) want to go to the park, this is:

N = 225*0.333% = 74.925

We can roud it up, and get N = 75

So Sally can expect that 75 students want to go to the park

4 0
3 years ago
Can the sides of a triangle have lengths 1, 3, and 10?
Troyanec [42]

Answer:

yes the sides of a triangle can have all those sides

3 0
3 years ago
Quality control is an important issue at ACME Company which manufacturers light bulbs. In order to conduct testing of the life h
mrs_skeptik [129]

Answer: 3424.28

Step-by-step explanation:

Given data : 378, 361, 350, 375, 200, 391, 375, 368,  321

Number of data values = 9

Mean :\overline{x}=\dfrac{\sum^n_{i=1} x_i}{n}

\\\\=\dfrac{378+361+350+375+200+391+375+368+321}{9}\\\\=\dfrac{3119}{9}\approx346.56

Variance = \dfrac{\sum^n_{i=1} (x_i-\overline{x})^2}{n-1}

\sum^n_{i=1} (x_i-\overline{x})^2 = (31.44)^2+(14.44)^2+(3.44)^2+(28.44)^2+(-146.56)^2+(44.44)^2+(28.44)^2+(21.44)^2+(-25.56)^2\\\\=27394.2224

Variance = \dfrac{27394.2224}{8}=3424.2775\approx3424.28

4 0
3 years ago
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