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Ivanshal [37]
2 years ago
15

Anyone know this two questions I can't figure this out

Mathematics
2 answers:
ozzi2 years ago
6 0

Answer:

22) x - 46 = 74

23) 20 portions

Step-by-step explanation:

21)

Let x = the number of cars Sara sold.

Jerry sold 46 cars fewer than Sara, so Jerry sold x - 46 cars.

Jerry sold 74 cars, so the equation is

x - 46 = 74

Answer: x - 46 = 74

22)

Let the number of 1/3 lb portions = x

The weight of x number of 1/3-lb portions is 1/3 * x, or simply x/3.

The full bag weighs 6 2/3 lb.

The equation is

x/3 = 6 2/3

Now we solve for x.

x/3 = 20/3

Multiply both sides by 3.

x = 20

Answer: 20 portions

omeli [17]2 years ago
3 0

Answer:

let 's' = Sara's amount

let 's-46' = Jerry's amount

equation:  s - 46 = 74

s = 120

Step-by-step explanation:

2nd question:  \frac{20}{3} ÷ \frac{1}{3} = \frac{20}{3}· \frac{3}{1} = 20

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(2-4d)(2+4d)=0<br> Help please, Its the 0 property
lianna [129]

Answer:

d1=-1/2,d2=1/2

Step-by-step explanation:

hope this helps

4 0
3 years ago
How do I solve this equation?
Gnom [1K]

2x(4-x)^{-1/2}-3(4-x)^{1/2}=(4-x)^{-1/2}\bigg(2x-3(4-x)\bigg)

We effectively rewrite the equation as

\dfrac{5x-12}{(4-x)^{1/2}}=0

In order for the LHS to be defined, we need to restrict 4-x>0, or x. Now, the LHS will vanish when the numerator is 0, which happens for

5x-12=0\implies5x=12\implies x=\dfrac{12}5

This value is indeed smaller than 4, so the solution is x=\dfrac{12}5.

8 0
3 years ago
PLEASE....I need help on this!
Kaylis [27]

15,567 because yeah i know math

6 0
3 years ago
Rico walked for 3/10 mile. Then he walked for 24/100 mile. How far did he walk in all?
grigory [225]
First, Rico walked for 3/10 of a mile which is 30/100 of a mile.
Hen, Rico walked for 24/100 of a mile.
Then you add 24/100 and 30/100. 24+30/100 which is 54/100.
Answer=54/100 of a mile
4 0
3 years ago
Read 2 more answers
Solve the following system of equations using elimination (Do not multipy)
aivan3 [116]
1) 5x - 6y = -32 --> equation 1
    3x + 6y = 48  --> equation 2
eliminating y from both of the equations and adding the rest of the terms
we get,
    8x = 16
    dividing 8 on both sides
    x = 2
Substituting the value of x in equation 1
   5(2) - 6y = -32
    10 - 6y = -32
   -6y = -12 ( dividing both sides by -6)
    y = 2

2) 
-3x - 3y = 9 ---> equation 1
      3x - 4y = 5 --> equation 2
eliminating x from both equations and adding the rest of the terms
 we get,
     -7y = 14 ( dividing both sides by -7 )
      y = -2
Substituting the value of y in the equation 1
    -3x - 3(-2) =9
    -3x + 6 = 9 (subtracting both sides by -6)
     -3x = 3
     x = -1

Hope this helps you..  :)
5 0
3 years ago
Read 2 more answers
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