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3 years ago

Line cd has endpoints c(1,4) and d(5,0) line ef has endpoints (4,5) and (2,-1).

Mathematics

2 answers:

amm18123 years ago

8 0

Answer:

yo what up

Step-by-step explanation:

Snezhnost [94]3 years ago

7 0

Answer:

gimme dem points

Step-by-step explanation:

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A camper attaches a rope from the top of her tent, 4 feet above the ground, to give it more support. If the rope is 8 feet long,

artcher [175]

8ft is the length of the rope on the outside of the tent. I hope its right!

7 0

3 years ago

The local branch of the Internal Revenue Service spent an average of 21 minutes helping each of 10 people prepare their tax retu

AURORKA [14]

Answer:

The confidence Interval is [- 0.7053 10.4521]

a: The hypotheses are

H0: μ1=μ2 against the claim Ha :μ1≠μ2

b. The critical value for t∝/2 for 17 d.f t > 2.508 and t < -2.111

c. t= -2.8422

d. The calculated value of t= -2.8422 is less than t < -2.11 the critical value therefore we reject H0 and conclude there is a difference between the two means.

Step-by-step explanation:

When the standard deviations are not the same then the confidence intervals for mean differences are calculated as

(x1`-x2`)- t∝/2 √s1²/n1 + s2²/n2 < u1-u2 < (x1`-x2`)+ t∝/2 √s1²/n1 + s2²/n2

x1`= 21 x2`= 27

n1= 10 n2= 14

s1= 5.6 s2= 4.3

The degrees of freedom is calculated using

υ = [s₁²/n1 + s₂²/n2]²/ (s₁²/n1 )²/ n1-1 + (s₂²/n2)²/n2-1

= 17

The t∝/2 for 17 d.f = 2.11

Putting the values

(x1`-x2`)- t∝/2 √s1²/n1 + s2²/n2 < u1-u2 < (x1`-x2`)+ t∝/2 √s1²/n1 + s2²/n2

(21-27) - 2.11√5.6²/10+ 4.3²/14 < u1-u2 <(21-27) +2.11√5.6²/10+4.3²/14

6- 2.11*2.111 < u1-u2 < ( 6 ) +2.11*2.111

6- 4.4521 < u1-u2 < ( 6 ) +5.294

- 1.5479 < u1-u2 < 10.4521

The confidence Interval is [- 0.7053 10.4521]

a: The hypotheses are

H0: μ1=μ2 against the claim Ha :μ1≠μ2

The claim is that there is a difference in the average time spent by the two services

b. The critical value for t∝/2 for 17 d.f t > 2.508 and t < -2.111

The degrees of freedom is calculated using

υ = [s₁²/n1 + s₂²/n2]²/ (s₁²/n1 )²/ n1-1 + (s₂²/n2)²/n2-1

= 17

c. The test statistic is

t= (x1`-x2`) /√s1²/n1 + s2²/n2

t= (21-27) /√5.6²/10+ 4.3²/14

t= -6/2.111

t= -2.8422

d. The calculated value of t= -2.8422 is less than t < -2.11 the critical value therefore we reject H0 and conclude there is a difference between the two means.

5 0

3 years ago

If k is a positive integer and n = k(k + 7), is n divisible by 6 ? (1) k is odd. (2) When k is divided by 3, the remainder is 2.

olganol [36]

Answer:

1.) Yes

2.) Yes

Step-by-step explanation:

Given that

n = k(k + 7)

If k is a positive integer and n = k(k + 7), is n divisible by 6 ?

(1) k is odd. Yes.

Let assume that k = 3

Then, n = 3(3 + 7)

n = 3 × 10

n = 30.

30 is divisible by 6.

(2) When k is divided by 3, the remainder is 2. That is,

Let k = 5

Then,

5/3 = 1 remainder 2

Substitute k into the equation

n = k(k + 7)

n = 5(5 + 7)

n = 5 × 12

n = 60

And 60 is divisible by 6.

Therefore, the answer to both questions is Yes.

5 0

3 years ago

I don’t really get this one.<br> Thx and have a great day!!

gayaneshka [121]

Answer:

The correct option is C). (9,4)

The coordinates of a point N is (9,4)

Step-by-step explanation:

Theory: If point P(x,y) lies on line segment AB and AP: PB=m:n, then we say P divides line AB internally in ratio of m:n and Point is given by

P= $(\frac{mX2+nX1}{m+n} , \frac{mY2+nY1}{m+n})$

Given that point, M is lying somewhere between point L and point N.

The coordinates of a point L is (-6,14)

The coordinates of a point M is (-3,12)

Also, LM: MN = 1:4

We can write as,

Let,

Point L(-6,14)=(X1, Y1)

Point M(-3,12)=(x,y)

Point N is (X2, Y2)

m=1 and n=4

M(-3,12)= $(\frac{mX2+nX1}{m+n} , \frac{mY2+nY1}{m+n})$

M(-3,12)= $(\frac{1(X2)+4(-6)}{1+4} , \frac{(Y2)+4(14)}{1+4})$

M(-3,12)= $(\frac{(X2)-24}{5} , \frac{1(Y2)+56}{5})$

$(-3)=\frac{(X2)-24}{5}$

(-15)=X2-24

X2=9

$(12)=\frac{(Y2)+56}{5}$

(60)=Y2+56

Y2=4

Thus,

The coordinates of a point N is (9,4)

Result: The correct option is C). (9,4)

3 0

3 years ago

At the end of her work day, Rosa leaves her office and goes directly to her bank. On the graph that shows the locations of Rosa'

ikadub [295]

Find the distance between the point of bank and the point of office.

$\sqrt{(x2 - x1)^{2}+ (y2 - y1)^{2}}$
$\sqrt{(-4 - (-6)^2 + (4 - (-3)^2}$
$\sqrt{(2)^2 + (7)^2}$
$\sqrt{4 + 49}$
$\sqrt{53}$

The distance she travels is approximately 7.3 km.

Hope this helps :)

7 0

3 years ago

Line cd has endpoints c(1,4) and d(5,0) line ef has endpoints (4,5) and (2,-1).​

Line cd has endpoints c(1,4) and d(5,0) line ef has endpoints (4,5) and (2,-1).