Answer:
The entire area of the sailboat is 60cm²
Step-by-step explanation:
You can find the area of this shape by breaking it down into simpler shapes and adding up their individual areas.
In this case, the areas we'll use are the rectangle at the bottom, and the pair of triangles at the top.
Because the two triangles can be put together to form a single triangle, we don't need to measure them independently. We can simply take the total length of their bases, multiply it by their height, and divide by two. This follows the rule that the area of a triangle is equal to the area of the square that contains it divided by two.
(2cm + 3cm) × 6cm
= 5cm × 6cm
= 30cm²
The rectangle's area is of course equal to its width times its height, so we can say:
2.5cm × 12cm
= 30cm²
The total area of the shapes then is 30cm² + 30 cm², giving us a total area of 60cm²
the angle 4pi/5 in quadrent 2
Answer:
1. x=34
2. c=8
3. x=9
4. m=32
That the answer for all 4.
Step-by-step explanation: Hope this help :D
Answer:
x=10 and y=12
Step-by-step explanation:
To solve this quadratic equation we will use two method
1. Elimination method
2. substitution method
first of we use elimination method
we either eliminate x or y
we will be eliminating y
83x-20y=590..........(eq1)
60x+18y=816...........(eq2)
y will be eliminated by multiplying
(eq1) by 9
(eq2) by 10
which will give
747x-180y=5310.........(eq3)
600x-180y=8160.........(eq4)
see that y has the same value that is (-180y and +180y)
so to eliminate y completely you have to add eq1 and eq2 because if you don't add them together you wont eliminate y
747x-180y=5310
+
600x+180y=8160
=
1347x+0=13470
1347x=13470
x=13470/1347
x=10
Now to find y we use substitution method ie put x=10 in any of the equation above(eq1,eq2,eq3, eq4) you will get the same answer
eq1
83x-20y=590..... where (x=10)
83(10)-20y =590
830-20y=590
like terms
-20y=590-830
-20y= -240
divide both sides with -20
y= -240/-20
y=12
OR
eq2
60x+18y=816..... where x=10
60(10)+18y=816
600+18y=816
like term
18y=816-600
18y=216
y=216/18
y= 12
or eq3 or eq4 you will still get the same answer......
