All categories

2 years ago

A square has a side length of 10cm. Work out the length of a diagonal of the square.

Mathematics

2 answers:

GarryVolchara [31]2 years ago

8 0

d=√2

a=√2.10 ≈14.14214cm

=14.14cm

Vitek1552 [10]2 years ago

5 0

Answer: Let x = the length of a side of the square

a2 + b2 = c2

x2 + x2 = 102

2x2 = 100

x2 = 50

x = √50

x = 5√2 cm

Step-by-step explanation:

You might be interested in

Please help!!! Thank you!!!

Reptile [31]

To find the total area of this figure, it would be easiest to find the area of the left part (rectangle) and then find the area of the right part (triangle), and then add the two area values together.

First, we will find the area of the rectangle, using the formula A = lw, where l is the length of the rectangle and w is the width of the rectangle.
The length of the rectangle is 13 cm and the width is 9 cm. If we substitute in these values into our equation, we get:
A = (13cm)(9cm)
A= 117 cm^2

Next, let’s find the area of the triangle, using the formula A=(1/2)bh, where b is the base of the triangle and h is the height.
The base of the triangle is 11 cm and the height of the triangle is 5 cm (found by subtracting 13-8 as seen in the figure). If we substitute in these values and simplify, we get:
A=1/2(11cm)(5cm)
A=1/2(55cm^2)
A=27.5 cm^2.

When we add together the area of the rectangle with the area of the triangle, we will get the total area of the figure.

117 cm^2 + 27.5 cm^2 = 144.5 cm^2
Your answer is 144.5 cm^2 or the first option.

Hope this helps!

8 0

3 years ago

Need help ASAP please

viva [34]

It would be 3,8
https://www.bing.com/videos/search?q=how+to+solve+a+slope+intercept+form&docid=608053494459401091&mi...
Watch this video it helped to understand how to do these

4 0

3 years ago

Which equation demonstrates the additive identity property?

Mrrafil [7]

Answer:

Step-by-step explanation:

Solve for o in the equation (7 + 4) + (7 - 41) = 14©(7 + 4) + 0 = 7 + 41o(7 + 4)(1) = 7 + 41o(7 + 41) + ( - 7 - 41) = 0

We first need to simplify the expression removing parentheses

Simplify 41o(7 + 4): Distribute the 41o to each term in (7+4)

41o * 7 = (41 * 7)o = 287o 41o * 4 = (41 * 4)o = 164o

Our Total expanded term is 287o + 164o

Simplify 41o(7 + 41): Distribute the 41o to each term in (7+41)

41o * 7 = (41 * 7)o = 287o 41o * 41 = (41 * 41)o = 1681o

Our Total expanded term is 287o + 1681o

Our updated term to work with is (7 + 4) + (7 - 41) = 14©(7 + 4) + 0 = 7 + 287o + 164o(1) = 7 + 287o + 1681o + ( - 7 - 41) = 0

We first need to simplify the expression removing parentheses

Simplify 164o(1): Distribute the 164o to each term in (1)

164o * 1 = (164 * 1)o = 164o Our Total expanded term is 164o

Our updated term to work with is (7 + 4) + (7 - 41) = 14©(7 + 4) + 0 = 7 + 287o + 164o = 7 + 287o + 1681o + ( - 7 - 41) = 0

Step 1: Group variables: We need to group our variables (7 and 14©(7. To do that, we subtract 14©(7 from both sides (7 - 14©(7 = 14©(7 - 14©(7

Step 2: Cancel 14©(7 on the right side: 0o = 0 Step 3: Divide each side of the equation by 0

5 0

3 years ago

Why might you want to round to the nearest hundred rather than the nearest ten

Luba_88 [7]

To obtain a more accurate answer! :)

8 0

3 years ago

Read 2 more answers

In triangle ABC, P is a centroid on a median AD. If AD=33 and AP>PD find AP

jasenka [17]

Answer:

AP = 22

Step-by-step explanation:

In a triangle, the centroid divides the median in the ratio 2:1.

It is given that AD is the median and AD = 33

It is also given that P is the centroid on the median AD.

Therefore, P divides AD in the ratio 2:1.

$\frac{AP}{PD} =\frac{2}{1}$

AP = 2k and PD = k

AD = 33

AP + PD = 33

2k + k = 33

3k = 33

k = 11

So, AP = 2k = 2(11) = 22

7 0

3 years ago

A square has a side length of 10cm. Work out the length of a diagonal of the square.​

A square has a side length of 10cm. Work out the length of a diagonal of the square.