We can tell which acid which have the highest percent ionization on the basis of pH value.
<h3>What is percent ionization?</h3>
The % ionized indicates how much of the original chemical has ionized. As a result, we compare the ion concentration in solution to the neutral species' original concentration.
If any acid have a high pH value then they must show high percent ionization because they are strong in nature and show full dissociation.
Hence acids with high pH value will show highest percent ionization.
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Electrons are negatively charged particles while protons that are found in the nucleus are positively charged. In the natural scheme of things, positive and negative charge produces an attractive force that pulls one particle towards the other. However, based on Rutherford's model of an atom, which is the planetary model that conclusively suggests that electrons revolve around the nucleus, such attraction between the two opposing particles creates an electromagnetic force that enables electrons to move around the positive nucleus thus preventing the electrons from spiraling towards it.
The question is incomplete, the complete question is;
The compound magnesium nitrate is a strong electrolyte. Write the reaction when magnesium nitrate is put into water:
Answer:
Mg(NO3)2(s)--------->Mg^2+(aq) + 2NO3^-(aq)
Explanation:
When we say that a compound is a strong electrolyte, we mean that that the compound dissociates completely in solution to form its ions.
This means that all strong electrolytes attain 100% dissociation of the solid in water according to its stoichiometric equation.
For magnesium nitrate, the reaction equation is;
Mg(NO3)2(s)--------->Mg^2+(aq) + 2NO3^-(aq)
The given concentration of boric acid = 0.0500 M
Required volume of the solution = 2 L
Molarity is the moles of solute present per liter solution. So 0.0500 M boric acid has 0.0500 mol boric acid present in 1 L solution.
Calculating the moles of 0.0500 M boric acid present in 2 L solution:
Converting moles of boric acid to mass:
Therefore, 6.183 g boric acid when dissolved and made up to 2 L with distilled water gives 0.0500 M solution.