.......the answer is a gas
A mixture that results when substances dissolve to form a homogeneous mixture is a solution.
Answer:
ΔS = 16.569 J/K
Explanation:
In this case, we need to use the correct expression to solve this. In thermodynamics, the expression to use that puts a relation between heat, temperature and entropy is the following:
ΔS = Q/T
To determine the entropy change of the universe, we need to sum the entropy change of Earth and the entropy of the sun.
As the sun is transfering radiation to Earth, the sun is losing energy, therefore, heat is negative, while Earth receives the heat, so it's positive. Calculating the entropy for the sun and Earth:
ΔSs = -Q/Ts
ΔSe = Q/Te
ΔSu = ΔSe + ΔSs
Let's calculate both entropies by separate:
ΔSe = 5x10^3 / 285 = 17.54 J/K
ΔSs = -5x10^3 / 5,150 = -0.971 J/K
Therefore, the entropy of universe:
ΔSu = 17.54 - 0.971
ΔSu = 16.569 J/K
Answer:
The value of the missing equilibrium constant ( of the first equation) is 1.72
Explanation:
First equation: 2A + B ↔ A2B Kc = TO BE DETERMINED
⇒ The equilibrium expression for this equation is written as: [A2B]/[A]²[B]
Second equation: A2B + B ↔ A2B2 Kc= 16.4
⇒ The equilibrium expression is written as: [A2B2]/[A2B][B]
Third equation: 2A + 2B ↔ A2B2 Kc = 28.2
⇒ The equilibrium expression is written as: [A2B2]/ [A]²[B]²
If we add the first to the second equation
2A + B + B ↔ A2B2 the equilibrium constant Kc will be X(16.4)
But the sum of these 2 equations, is the same as the third equation ( 2A + 2B ↔ A2B2) with Kc = 28.2
So this means: 28.2 = X(16.4)
or X = 28.2/16.4
X = 1.72
with X = Kc of the first equation
The value of the missing equilibrium constant ( of the first equation) is 1.72
