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elena-s [515]
2 years ago
5

Simplify. √3(√6+√15)

Mathematics
2 answers:
Vikentia [17]2 years ago
8 0

Answer:

10.9508446196

hope it helps

Igoryamba2 years ago
8 0
Not sure if you need it without rounding or anything, but in its exact form, the answer is 3√2 + 3√5.

Explanation: You take √3 and carry it to √6 and √15. This means doing √3 times √6 and √3 times √15. Doing so gives you √18 + √45. Simplifying the roots would give you 3√2 + 3√5. How you get from √18 to 3√2 is that you make a factor tree of 18. Any factor that is the same will be added to the coefficient. In this case, 3 would have to be your coefficient. The factors of 18 are 2, 3, and 3. If there are two of the same factors, you put them together as one. (In this case, the two 3’s would become one 3.) How you get from √45 to 3√5 is doing the exact same process that happened from getting √18 to 3√2 except you would make a factor tree of 45. (The factors of 45 are 5, 3, and 3. Two 3’s make one 3.) Therefore, your answer in exact form would be 3√2 + 3√5.
I hope this helps. Sorry if I did not understand the question correctly.
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Answer:

Step-by-step explanation:

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A publisher needs to send many books to a local book retailer and will send the books in a combination of small and large boxes.
Paladinen [302]

Answer:

Answer:

\{ {{20x+30y=280} \atop {y=4x}} .{

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Step-by-step explanation:

Let be xx the number of small boxes sent and yy the number of large boxes sent.

Since each small box can hold 20 books (20x20x ), each large box can hold 30 books (30y30y )and altogether can hold a total of 280 books, we can write the following equation to represent this:

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According to the information provided in the exercise, there were 4 times as many large boxes sent as small boxes. This can be represented with this equation:

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Therefore, the system of equation that be used to determine the number of small boxes sent and the number of large boxes sent, is:

\{ {{20x+30y=280} \atop {y=4x}} .{

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3 years ago
Which formula should I use?
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V=πr²h

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