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3 years ago

Simplify. √3(√6+√15)

Mathematics

2 answers:

Vikentia [17]3 years ago

8 0

Answer:

10.9508446196

hope it helps

Igoryamba3 years ago

8 0

Not sure if you need it without rounding or anything, but in its exact form, the answer is 3√2 + 3√5.

Explanation: You take √3 and carry it to √6 and √15. This means doing √3 times √6 and √3 times √15. Doing so gives you √18 + √45. Simplifying the roots would give you 3√2 + 3√5. How you get from √18 to 3√2 is that you make a factor tree of 18. Any factor that is the same will be added to the coefficient. In this case, 3 would have to be your coefficient. The factors of 18 are 2, 3, and 3. If there are two of the same factors, you put them together as one. (In this case, the two 3’s would become one 3.) How you get from √45 to 3√5 is doing the exact same process that happened from getting √18 to 3√2 except you would make a factor tree of 45. (The factors of 45 are 5, 3, and 3. Two 3’s make one 3.) Therefore, your answer in exact form would be 3√2 + 3√5.
I hope this helps. Sorry if I did not understand the question correctly.

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A researcher is studying the monthly gross incomes of drivers for a ride sharing company. (Gross incomes represent the amount pa

Reptile [31]

Answer:

The histogram of the sample incomes will follow the normal curve.

Step-by-step explanation:

According to the Central Limit Theorem if we have an unknown population with mean μ and standard deviation σ and appropriately huge random samples (n > 30) are selected from the population with replacement, then the distribution of the sample mean will be approximately normally distributed.

In this case the researches wants to determine the monthly gross incomes of drivers for a ride sharing company.

He selects a sample of n = 200 drivers and ask them their monthly salary.

As the sample selected is quite large, i.e. n = 200 > 30, the central limit theorem can be applied to approximate the sampling distribution of sample mean by the Normal distribution.

Thus, the histogram of the sample incomes will follow the normal curve.

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3 years ago

8+(3+4) rewrite using the associative property

Goshia [24]

The Associative Property allows you to "regroup" addition and multiplication problems. You can group this problem in two other ways,
(8 + 4) + 3 and (8 + 3) + 4.

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3 years ago

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A train traveled 504 miles in 8 hours. A bus traveled 531 miles in 9 hours. Which mode of transportation has the faster rate?

OlgaM077 [116]

The train because it travels at 63 mph while the bus is 59 mph

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2 years ago

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Rectangle STUV is shown on a coordinate plane. Rectangle STUV with vertices S at negative 7 comma 6, T at negative 2 comma 6, U

rusak2 [61]

The coordinate of the point T after the given transformations is; T''(-2, -4)

<h3>How to carry out Translation Transformations?</h3>

We are given the coordinates of the rectangle STUV as;

S(-7, 6)

T(-2, 6)

U(-2, 1)

V(-7, 1)

Now, we are told that all these coordinates are translated using the transformation rule; (x, y) → (x − 2, y − 4)

Thus, the new coordinates using this transformation rule are;

S'(-9, 2)

T'(-4, 2)

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Now, we are told that these new points are rotated 90° counterclockwise and as such the new coordinates formed will follow the pattern (x, y) → (-y, x).

Thus, our final coordinates are;

S''(-2, -9)

T''(-2, -4)

U''(3, -4)

V''(3, -9)

Thus, the coordinate of the point T after the given transformations is; T''(-2, -4)

Read more about Translation Transformation at; brainly.com/question/4289712

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2 years ago

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What percentage of the semi circle is shaded?

mezya [45]

The percentage of the semicircle shaded section is approximately 23,606 %.

The percentage of the area of the semicircle is equal to the ratio of the semicircle area minus the half-cross area to the semicircle area. In other words, we have the following expression:

$r = \left(\frac{A_{s}-A_{h}}{A_{s}} \right)\times 100\,\%$

$r = \left(1-\frac{A_{h}}{A_{s}} \right)\times 100\,\%$ (1)

Where:

$A_{h}$ - Area of the half cross, in square centimeters.
$A_{s}$ - Area of the semicircle, in square centimeters.
$r$ - Percentage of the shaded section of the semicircle.

And the percentage of the shaded section is:

$r = \left[1-\frac{4 \cdot (2\,cm)^{2}+4\cdot \left(\frac{1}{2} \right)\cdot (2\,cm)^{2}}{0.5\cdot \pi\cdot (16\,cm^{2}+4\,cm^{2})} \right]\times 100$

$r \approx 23.606\,\%$

The percentage of the semicircle shaded section is approximately 23,606 %.

We kindly invite to check this question on percentages: brainly.com/question/15469506

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2 years ago