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3 years ago

6

Suppose that when your friend was born , your friends parents deposited 4000 in an account paying 5.8 % interest compounded quar

terly . What will the account balance be after 14 years

1 answer:

tresset_1 [31]3 years ago

4 0

56,000$

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Jane is studying the weather in Alaska. she recorded the temperature for four days in January, in degrees Fahrenheit, as shown i

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Ji-Hun and Kana are running a marathon. Due to the volume of people running, the starts occur in waves. Kana starts at 9:35 a.m.

iris [78.8K]

Answer:

23.52 miles

Step-by-step explanation:

Let us find the number of miles that they would have run.

Kana starts at 9:35 a.m. and runs at an average rate of 7 mph.

Let the time she has spent so far be t.

Speed is given as:

s = d / t

where d = distance and t = time

=> d = s * t

Therefore, for Kana:

d = 7 * t = 7t _____________(1)

Ji-Hun starts at 10:00 am (25 minutes after Hannah) and runs at an average rate of 8 mph.

25 minutes = 25/60 hour = 0.42 hour

So, his time (compared to Kana's) is t - 0.42.

therefore, for Ji-Hun:

d = 8 * (t - 0.42)

=> d = 8t - 3.36 ____________(2)

Equating (1) and (2):

7t = 8t - 3.36

=> 8t - 7t = 3.36

t = 3.36 hours

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3 years ago

What is the probability that a randomly selected male will have a foot length between 8 and 12.5 inches? P(8 < r < 12.5)=

melisa1 [442]

Answer:

0.8185 or 81.85%

Step-by-step explanation:

The mean length (μ) of an adult foot is 11 and the standard deviation (σ) is 1.5.

The z score is a measure in statistic used to determine the amount of standard deviation by which the raw score (x) is above or below the mean. If the raw score is above the mean, the z score is positive and if the raw score is below the mean the z sore is negative. It is given by:

$z=\frac{x-\mu}{\sigma}$

To calculate the probability that a randomly selected male will have a foot length between 8 and 12.5 inches, we first calculate the z score for 8 inches and then for 12.5 inches.

For 8 inches:

$z=\frac{x-\mu}{\sigma}=\frac{8-11}{1.5}=-2$

For 12.5 inches:

$z=\frac{x-\mu}{\sigma}=\frac{12.5-11}{1.5}=1$

From the normal distribution table, The probability that a randomly selected male will have a foot length between 8 and 12.5 inches = P(8 < x < 12.5) = P(-2 < z < 1) = P(z < 1) - P(z < -2) = 0.8413 - 0.0228 = 0.8185 = 81.85%

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