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3 years ago

Which of the following is the standard form of the equation 5x2 - 20x = 15?

2 answers:

4 0

It is C. The first part is raised to the 2nd power. so it goes first since that is the highest. then the -20x because variables are understood to the power of 1, while normal numbers are understood to the power of 0. so the order is highest to lowest (2,1,0)

Nuetrik [128]3 years ago

4 0

$5x^2 - 20x = 15$

Divide both sides by 5, it would give :

$x^2-4x=3$

After it gives :

$x^2-4x-3=0$

So the answer would be : B.

Hope this helps !

Photon

You might be interested in

What is the answer for (1/2 divided by 2/7) divided by 4/3

Kaylis [27]

Answer:

1.3125

Step-by-step explanation:

1/2 divided by 2/7 is 1.75

1.75 divided by 4/3 equals 1.3125

6 0

2 years ago

If 180° < α < 270°, cos⁡ α = −817, 270° < β < 360°, and sin⁡ β = −45, what is cos⁡ (α + β)?

eduard

Answer:

$cos(\alpha+\beta)=-\frac{84}{85}$

Step-by-step explanation:

we know that

$cos(\alpha+\beta)=cos(\alpha)*cos(\beta)-sin(\alpha)*sin(\beta)$

Remember the identity

$cos^{2} (x)+sin^2(x)=1$

step 1

Find the value of $sin(\alpha)$

we have that

The angle alpha lie on the III Quadrant

The values of sine and cosine are negative

$cos(\alpha)=-\frac{8}{17}$

Find the value of sine

$cos^{2} (\alpha)+sin^2(\alpha)=1$

substitute

$(-\frac{8}{17})^{2}+sin^2(\alpha)=1$

$sin^2(\alpha)=1-\frac{64}{289}$

$sin^2(\alpha)=\frac{225}{289}$

$sin(\alpha)=-\frac{15}{17}$

step 2

Find the value of $cos(\beta)$

we have that

The angle beta lie on the IV Quadrant

The value of the cosine is positive and the value of the sine is negative

$sin(\beta)=-\frac{4}{5}$

Find the value of cosine

$cos^{2} (\beta)+sin^2(\beta)=1$

substitute

$(-\frac{4}{5})^{2}+cos^2(\beta)=1$

$cos^2(\beta)=1-\frac{16}{25}$

$cos^2(\beta)=\frac{9}{25}$

$cos(\beta)=\frac{3}{5}$

step 3

Find cos⁡ (α + β)

$cos(\alpha+\beta)=cos(\alpha)*cos(\beta)-sin(\alpha)*sin(\beta)$

we have

$cos(\alpha)=-\frac{8}{17}$

$sin(\alpha)=-\frac{15}{17}$

$sin(\beta)=-\frac{4}{5}$

$cos(\beta)=\frac{3}{5}$

substitute

$cos(\alpha+\beta)=-\frac{8}{17}*\frac{3}{5}-(-\frac{15}{17})*(-\frac{4}{5})$

$cos(\alpha+\beta)=-\frac{24}{85}-\frac{60}{85}$

$cos(\alpha+\beta)=-\frac{84}{85}$

4 0

3 years ago

What is the solution of the system? Use either the substitution method or the elimination method. 4x + 2y = 104x + 2y = 10 x − y

bixtya [17]

4x+2y=10 Equation 1
x-y=13 Equation 2
Solving by substitution method.
Isolate x from equation 2.
x=y+13
Substitute value of x in equation 1
4(y+13)+2y=10
4y+52+2y=10
6y+52=10
6y=-42
y=-7
Now substitute value of y in x=y+13
x=-7+13
x=6

Answer: (6,-7)

8 0

3 years ago

Find the value of x.

svetoff [14.1K]

Answer:

Step-by-step explanation:

1) Find the interior angle using relations of angles in straight line I.e ( sum of angles in a straight line is 180 ) and we know the sum of all the interior angle of quadrilateral is 360 degree .

2) Solve further for x.

5 0

2 years ago

The length of the flower garden is 3 times as great as the width. What are the dimensions? The area is 48 sq m

Rudiy27

The correct answer is 144

8 0

3 years ago