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joja [24]
3 years ago
6

Help me pretty plase

Mathematics
2 answers:
Brut [27]3 years ago
5 0

Answer:

Irrational

Step-by-step explanation:

Hope this helps

belka [17]3 years ago
5 0
The answer is (irrational)
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Place a set of parentheses in the expression so that its value is 33. 48-5+2x3+6
Xelga [282]
The parentheses must be placed here <span>48 - (5 + 2) * 3 + 6 in order for the equation to equal 33. </span>

4 0
4 years ago
Which is the best buy?
gogolik [260]

Answer:

A

Step-by-step explanation:

work out price of each for one bottle

A) $12.60 ÷ 7 = $1.80

B) $10.98 ÷ 6 = $1.83

C) $18.10 ÷ 10 = $1.81

D) $16.38 ÷ 9 = $2.82

we can clearly see that A is the cheapest

5 0
3 years ago
Read 2 more answers
Round 18.049 to the nearest tenth.
kirill115 [55]

Answer:

18.0

Step-by-step explanation:

Note the tenth place value (underlined and bolded): 18.<u>0</u>49

Look at the number to the direct right of the tenth place value (or the hundredth place value in this case). It is a 4.

Note the rules of rounding. If the number:

1) is 5 or greater, round up.

2) is 4 or less, round down.

In this case, it is 4, so you will round down.

18.049 rounded to the nearest tenth is 18.0

~

4 0
3 years ago
Read 2 more answers
Suppose after 2500 years an initial amount of 1000 grams of a radioactive substance has decayed to 75 grams. What is the half-li
krok68 [10]

Answer:

The correct answer is:

Between 600 and 700 years (B)

Step-by-step explanation:

At a constant decay rate, the half-life of a radioactive substance is the time taken for the substance to decay to half of its original mass. The formula for radioactive exponential decay is given by:

A(t) = A_0 e^{(kt)}\\where:\\A(t) = Amount\ left\ at\ time\ (t) = 75\ grams\\A_0 = initial\ amount = 1000\ grams\\k = decay\ constant\\t = time\ of\ decay = 2500\ years

First, let us calculate the decay constant (k)

75 = 1000 e^{(k2500)}\\dividing\ both\ sides\ by\ 1000\\0.075 = e^{(2500k)}\\taking\ natural\ logarithm\ of\ both\ sides\\In 0.075 = In (e^{2500k})\\In 0.075 = 2500k\\k = \frac{In0.075}{2500}\\ k = \frac{-2.5903}{2500} \\k = - 0.001036

Next, let us calculate the half-life as follows:

\frac{1}{2} A_0 = A_0 e^{(-0.001036t)}\\Dividing\ both\ sides\ by\ A_0\\ \frac{1}{2} = e^{-0.001036t}\\taking\ natural\ logarithm\ of\ both\ sides\\In(0.5) = In (e^{-0.001036t})\\-0.6931 = -0.001036t\\t = \frac{-0.6931}{-0.001036} \\t = 669.02 years\\\therefore t\frac{1}{2}  \approx 669\ years

Therefore the half-life is between 600 and 700 years

5 0
3 years ago
A polynomial function has roots –5 and 1. Which of the following could represent this function? f(x) = (x + 5)(x + 1) f(x) = (x
Dimas [21]

f(x) = (x + 5)(x - 1)

using the ' factor theorem '

given x = a is the root of a polynomial then (x - a ) is a factor

here roots are x = - 5 and x = 1 hence factors are (x + 5) and (x - 1)

the polynomial is the product of the factors

f(x) = (x + 5)(x - 1)


3 0
4 years ago
Read 2 more answers
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