Answer:
Step-by-step explanation:
Given that a young person with no initial capital invests k dollars per year at an annual rate of return r. Assume that investments are made continuously and that the return is compounded continuously
a) Amount accumulated at time t
, where r = rate of interest and t = time lapsed
b) Here S = 1,000,000

So 49802.56 dollars to be invested to get 1 million after 40 years
c) k = 2000 per year
I 2000 will be for 40 years, II 2000 for 39 years, ..... Last 2000 for 0 years
i.e. final amount would be
![2000[(e^{40r} +(e^{39r} +....e^r] = 1000000\\500 = \frac{e^r(e^{40r}-1}{e^r-1}](https://tex.z-dn.net/?f=2000%5B%28e%5E%7B40r%7D%20%2B%28e%5E%7B39r%7D%20%2B....e%5Er%5D%20%3D%201000000%5C%5C500%20%3D%20%5Cfrac%7Be%5Er%28e%5E%7B40r%7D-1%7D%7Be%5Er-1%7D)
solving we get r = 9.6% approxy