Answer:
y =3x - 5
Step-by-step explanation:
Well one of the way to do this question is the formula given below your question, but for me, i rather do it this way
OK they gave u y=3x - 12
And they say another line is parallel, once u see the word parallel means they have the same angle, same slope, same gradient ( sorry if I give u the wrong terms, since I learn mine in Malay)
So first u got to understand the slope-intercept form
y = mx + c
y is your y coordinate
x is your x coordinate
m is your gradient ( as in how much the line slants)
c is the y - intercept, as in, if u draw a graph, the y-coordinate where your line touches the y-axis (the vertical line)
So since the say the both lines are parallel, so both of their "m" is the same that is 3. Why? Cuz just compare
y = mx + c
y = 3x - 12
Therefore the m is 3
Therefore u alredy got your first value, so put it in your slope intercept form
y = mx + c
y = 3x + c
Now how to find c? Very easy, just put in the value of y and x from the coordinate ( that the line youre finding is on) they gave u, just put the value in
They gave u
(1, - 2)
So when x = 1, y = - 2
Therefore put it in
y = 3x + c
-2 = 3 (1) + c
c = - 5
Since now u have your m and c value, your slope intercept form is done, just put it in
y = mx + c
y = 3x + (-5)
y = 3x -5
determinati cel mai mic multiplu comun al urmatoarelor numere naturale a-36,48,54;b-30,45,75;c-48,60,72;d-90,24,72;e-75,100,150;
fenix001 [56]
<span>f-72,108,144 is the answer i hop it helps you</span>
Answer:
the answer is c i did the test
Step-by-step explanation:
pls i did the test trust me.
Answer:
4/7 (first one)
Step-by-step explanation:
6-(2)/(2)+5=4/7
hope this helps
Answer:
Elevation in boiling point is mathematically expressed as
ΔTb = Kb X m
where Kb = boiling point elevation constant = 2.53°c/m (for benzene)
m = molality of solution = 3.47 m (given)
∴ ΔTb = 2.53 X 3.47
= 8.779 oC
But, boiling point of benzene = 80.1 oC
∴ Boiling point of solution = 88.879 oC
Now, Depression in freezing point = ΔTf = Kf X m
where, Kf = freezing point depression constant = 5.12°c/m (for benzene)
∴ ΔTf = 5.12 X 3.47
= 17.766 oC
But freezing point of benzene = 5.5 oC
∴ Freezing point of solution = -12.266 oC
