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4 years ago

(1 pt)

1 answer:

7 0

The correct answer is choice D, or (-3, 2). We can tell because if we plot out the points, we go left 3, down 3 for (-3, -3), then right 7, down 3 for (7, -3), then right 7, up 2 for (7, 2), therefore the remaining point would have to be left -3, up 2, which is shown in choice D.
Hope that helped =)

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Use the triangles below to find the<br> trigonometric ratios.

anzhelika [568]

Hi I did my working on paper. You can see it in the photo.

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2 years ago

Solve the system with elimination. {2x-y=2, -5x+4y=-2

DaniilM [7]

Answer:

{x=2,y=2

Step-by-step explanation:

Equation 1:

Multiply both sides of the equation by a coefficient

{ 4(2x-y)=2*4

-5x+4y=-2

Apply Multiplicative Distribution Law

{8x-4y=2*4,-5x+4y=-2

8x-4y+(-5x+4y)=8+(-2)

Remove parentheses

8x-4y-5x+4y=8-2

Cancel one variable

8x-5x=8-2

Combine like terms

3x=8-2

Calculate the sum or difference

3x=6

Divide both sides of the equation by the coefficient of the variable

x=6/3

Calculate the product or quotient

x=2

Equation two:

{-5+4y=-2, x=2

-5*2+4y=-2

Calculate the product or quotient

-10+4y =-2

Reduce the greatest common factor (GCF) on both sides of the equation

-5+2y=-1

Rearrange unknown terms to the left side of the equation

2y=-1+5

Calculate the sum or difference

2y=4

Divide both sides of the equation by the coefficient of the variable

y=4/2

y=2

Hope this helps!!

6 0

2 years ago

Rockwell hardness of pins of a certain type is known to have a mean value of 50 and a standard deviation of 1.2.a. If the distri

zalisa [80]

Answer:

$P(\= X \ge 51 ) =0.0062$

$P(\= X \ge 51 ) = 0$

Step-by-step explanation:

From the question we are told that

The mean value is $\mu = 50$

The standard deviation is $\sigma = 1.2$

Considering question a

The sample size is n = 9

Generally the standard error of the mean is mathematically represented as

$\sigma_x = \frac{\sigma }{\sqrt{n} }$

=> $\sigma_x = \frac{ 1.2 }{\sqrt{9} }$

=> $\sigma_x = 0.4$

Generally the probability that the sample mean hardness for a random sample of 9 pins is at least 51 is mathematically represented as

$P(\= X \ge 51 ) = P( \frac{\= X - \mu }{\sigma_{x}} \ge \frac{51 - 50 }{0.4 } )$

$\frac{\= X -\mu}{\sigma } = Z (The \ standardized \ value\ of \ \= X )$

$P(\= X \ge 51 ) = P( Z \ge 2.5 )$

=> $P(\= X \ge 51 ) =1- P( Z < 2.5 )$

From the z table the area under the normal curve to the left corresponding to 2.5 is

$P( Z < 2.5 ) = 0.99379$

=> $P(\= X \ge 51 ) =1-0.99379$

=> $P(\= X \ge 51 ) =0.0062$

Considering question b

The sample size is n = 40

Generally the standard error of the mean is mathematically represented as

$\sigma_x = \frac{\sigma }{\sqrt{n} }$

=> $\sigma_x = \frac{ 1.2 }{\sqrt{40} }$

=> $\sigma_x = 0.1897$

Generally the (approximate) probability that the sample mean hardness for a random sample of 40 pins is at least 51 is mathematically represented as

$P(\= X \ge 51 ) = P( \frac{\= X - \mu }{\sigma_x} \ge \frac{51 - 50 }{0.1897 } )$

=> $P(\= X \ge 51 ) = P(Z \ge 5.2715 )$

=> $P(\= X \ge 51 ) = 1- P(Z < 5.2715 )$

From the z table the area under the normal curve to the left corresponding to 5.2715 and

=> $P(Z < 5.2715 ) = 1$

$P(\= X \ge 51 ) = 1- 1$

=> $P(\= X \ge 51 ) = 0$

5 0

3 years ago

If you make 1170 points out of 1800 what grade would I have

insens350 [35]

Answer:

req grade=35%

Step-by-step explanation:

req grade= $\frac{1800-1170}{1800}\times100$

req grade= $\frac{63000}{1800}$

req grade=35% answer

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4 years ago

What is 1/8y as a verbal expression

Alenkinab [10]

An algebraic expression consists of one or more numbers and variables, for 1/8y it will be y+1/8

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3 years ago