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3 years ago

Suma de polinomios de 5×³+3 + 2×³-×²+1 porfavor ayuda

Mathematics

1 answer:

Sidana [21]3 years ago

5 0

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Let's simplify step-by-step.

5x^3 + 3 + 2x^3 − x^2 + 1

= 5x^3 + 3 + 2x^3 + −x^2 + 1

Combine Like Terms:

= 5x^3 + 3 + 2x^3 + −x^2 + 1

= ( 5x^3 + 2x^3 ) + ( −x^2 ) + ( 3 + 1 )

= 7x^3 + −x^2 + 4

Answer:

= 7x^3 − x^2 + 4

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What is the y intercept of (-4,6) and (1,-9)

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Answer:

what is the y intercept of (-4,6) and (1,-9) : (3,-12)

Step-by-step explanation:

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22. A parabola equation is given as y = 3(x - 2)^2 + 5. What are the coordinates of the vertex?

sergiy2304 [10]

Answer:

(2, 5)

Step-by-step explanation:

The x coordinate is the number inside the parentheses, but with the opposite sign, 2

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How many square feet of outdoor carpet will we need for this hole

Fed [463]

Answer:

40 ft²

Step-by-step explanation:

The shape of the outdoor carpet can be decomposed into 2 triangles and 1 rectangle

✔️Area of triangle 1:

Area = ½*bh

b = 6 - 3 = 3 ft

h = 11 - 7 = 4 ft

Area of triangle 1 = ½*3*4 = 6 ft²

✔️Area of triangle 2:

Area = ½*by

b = 2 ft

h = 3 ft

Area of triangle 2 = ½*2*3 = 3 ft

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L = 11 ft

W = 3 ft

Area of rectangle = 11 × 3 = 33 ft

✅area of outdoor carpet = 4 + 3 + 33 = 40 ft²

4 0

3 years ago

Write an equation in slope-intercept form for the line that passes through (4,-3) and is parallel to the line described by y=1/2

Marat540 [252]

Given:

The point, (4, -3)

The line,

$y=\frac{1}{2}x+5$

To find an equation in slope-intercept form for the line that passes through (4,-3) and is parallel to the given line:

The slope of the line is,

$m=\frac{1}{2}$

Since the given line is parallel to the new line, so the slope will be same for the both.

Using the point-slope formula,

$y-y_1=m(x-x_1)$

Substitute the point and slope we get,

$\begin{gathered} y-(-3)=\frac{1}{2}(x-4) \\ y+3=\frac{1}{2}x-2 \\ y=\frac{1}{2}x-2-3 \\ y=\frac{1}{2}x-5 \end{gathered}$

Hence, the equation in slope-intercept form for the line is,

$y=\frac{1}{2}x-5$

8 0

1 year ago

A triangle is formed from the points L(-3, 6), N(3, 2) and P(1, -8). Find the equation of the following lines:

Dima020 [189]

Answer:

Part A) $y=\frac{3}{4}x-\frac{1}{4}$

Part B) $y=\frac{2}{7}x-\frac{5}{7}$

Part C) $y=\frac{2}{7}x+\frac{8}{7}$

see the attached figure to better understand the problem

Step-by-step explanation:

we have

points L(-3, 6), N(3, 2) and P(1, -8)

Part A) Find the equation of the median from N

we Know that

The median passes through point N to midpoint segment LP

step 1

Find the midpoint segment LP

The formula to calculate the midpoint between two points is equal to

$M(\frac{x1+x2}{2},\frac{y1+y2}{2})$

we have

L(-3, 6) and P(1, -8)

substitute the values

$M(\frac{-3+1}{2},\frac{6-8}{2})$

$M(-1,-1)$

step 2

Find the slope of the segment NM

The formula to calculate the slope between two points is equal to

$m=\frac{y2-y1}{x2-x1}$

we have

N(3, 2) and M(-1,-1)

substitute the values

$m=\frac{-1-2}{-1-3}$

$m=\frac{-3}{-4}$

$m=\frac{3}{4}$

step 3

Find the equation of the line in point slope form

$y-y1=m(x-x1)$

we have

$m=\frac{3}{4}$

$point\ N(3, 2)$

substitute

$y-2=\frac{3}{4}(x-3)$

step 4

Convert to slope intercept form

Isolate the variable y

$y-2=\frac{3}{4}x-\frac{9}{4}$

$y=\frac{3}{4}x-\frac{9}{4}+2$

$y=\frac{3}{4}x-\frac{1}{4}$

Part B) Find the equation of the right bisector of LP

we Know that

The right bisector is perpendicular to LP and passes through midpoint segment LP

step 1

Find the midpoint segment LP

The formula to calculate the midpoint between two points is equal to

$M(\frac{x1+x2}{2},\frac{y1+y2}{2})$

we have

L(-3, 6) and P(1, -8)

substitute the values

$M(\frac{-3+1}{2},\frac{6-8}{2})$

$M(-1,-1)$

step 2

Find the slope of the segment LP

The formula to calculate the slope between two points is equal to

$m=\frac{y2-y1}{x2-x1}$

we have

L(-3, 6) and P(1, -8)

substitute the values

$m=\frac{-8-6}{1+3}$

$m=\frac{-14}{4}$

$m=-\frac{14}{4}$

$m=-\frac{7}{2}$

step 3

Find the slope of the perpendicular line to segment LP

Remember that

If two lines are perpendicular, then their slopes are opposite reciprocal (the product of their slopes is equal to -1)

$m_1*m_2=-1$

we have

$m_1=-\frac{7}{2}$

$m_2=\frac{2}{7}$

step 4

Find the equation of the line in point slope form

$y-y1=m(x-x1)$

we have

$m=\frac{2}{7}$

$point\ M(-1,-1)$ ----> midpoint LP

substitute

$y+1=\frac{2}{7}(x+1)$

step 5

Convert to slope intercept form

Isolate the variable y

$y+1=\frac{2}{7}x+\frac{2}{7}$

$y=\frac{2}{7}x+\frac{2}{7}-1$

$y=\frac{2}{7}x-\frac{5}{7}$

Part C) Find the equation of the altitude from N

we Know that

The altitude is perpendicular to LP and passes through point N

step 1

Find the slope of the segment LP

The formula to calculate the slope between two points is equal to

$m=\frac{y2-y1}{x2-x1}$

we have

L(-3, 6) and P(1, -8)

substitute the values

$m=\frac{-8-6}{1+3}$

$m=\frac{-14}{4}$

$m=-\frac{14}{4}$

$m=-\frac{7}{2}$

step 2

Find the slope of the perpendicular line to segment LP

Remember that

If two lines are perpendicular, then their slopes are opposite reciprocal (the product of their slopes is equal to -1)

$m_1*m_2=-1$

we have

$m_1=-\frac{7}{2}$

$m_2=\frac{2}{7}$

step 3

Find the equation of the line in point slope form

$y-y1=m(x-x1)$

we have

$m=\frac{2}{7}$

$point\ N(3,2)$

substitute

$y-2=\frac{2}{7}(x-3)$

step 4

Convert to slope intercept form

Isolate the variable y

$y-2=\frac{2}{7}x-\frac{6}{7}$

$y=\frac{2}{7}x-\frac{6}{7}+2$

$y=\frac{2}{7}x+\frac{8}{7}$

7 0

3 years ago

Suma de polinomios de 5×³+3 + 2×³-×²+1 porfavor ayuda​

Suma de polinomios de 5×³+3 + 2×³-×²+1 porfavor ayuda