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Temka [501]
4 years ago
7

Can anyone please help : show that cos^{2} (θ)= 1 + cos(2θ) / 2 , using the compound angle formula

Mathematics
1 answer:
iragen [17]4 years ago
6 0

Answer:

Below

Step-by-step explanation:

Let's prove that cos^2(O) = 1+ cos(2O)/2

We khow that cos(2O) = 2 cos^2-1

● cos(2O) = 2 cos^2-1

Add one to both sides:

● cos(2O) +1 = 2 cos^2-1+1

● cos(2O) +1 = 2 cos ^2

Divide both sides by 2

● [cos(2O)+1]/2 = cos^2

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EXAMPLE 2 Prove that 9ex is equal to the sum of its Maclaurin series. SOLUTION If f(x) = 9ex, then f (n + 1)(x) = for all n. If
amm1812

Answer:

To Prove: 9e^x is equal to the sum of its Maclaurin series.

Step-by-step explanation:

If f(x) = 9e^x, then f ^{(n + 1)(x)} =9e^x for all n. If d is any positive number and   |x| ≤ d, then |f^{(n + 1)(x)}| = 9e^x\leq  9e^d.

So Taylor's Inequality, with a = 0 and M = 9e^d, says that |R_n(x)| \leq \dfrac{9e^d}{(n+1)!} |x|^{n + 1} \:for\: |x| \leq  d.

Notice that the same constant M = 9e^d works for every value of n.

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THEOREM\\If f(x)=T_n(x)+R_n(x), $where $T_n $is the nth degree Taylor Polynomial of f at a and  $ lim_{n\to\infty} R_n(x)=0 \:  for \: |x-a|

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