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Temka [501]
3 years ago
7

Can anyone please help : show that cos^{2} (θ)= 1 + cos(2θ) / 2 , using the compound angle formula

Mathematics
1 answer:
iragen [17]3 years ago
6 0

Answer:

Below

Step-by-step explanation:

Let's prove that cos^2(O) = 1+ cos(2O)/2

We khow that cos(2O) = 2 cos^2-1

● cos(2O) = 2 cos^2-1

Add one to both sides:

● cos(2O) +1 = 2 cos^2-1+1

● cos(2O) +1 = 2 cos ^2

Divide both sides by 2

● [cos(2O)+1]/2 = cos^2

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Which number<br> is between 2.23 and 2.24 on a number line?
Gekata [30.6K]

Answer:

There are infinity many numbers between 2.23 an 2.24, but if you want the exact middle, it's 2.235

Hope this helped :)

8 0
3 years ago
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Students at East Central High School earned $535 selling candles. They want to make $2570 for a club trip. What percent of their
satela [25.4K]

Answer:

21%

Step-by-step explanation:

\frac{100}{y}x=\frac{2570}{535}

Solving for x

x=535*100/2570              

x≈21%

6 0
3 years ago
How much money will you have in 6 years if you invest $1000 at 3% compounded monthly?
Ilia_Sergeevich [38]
i don’t know i really just need points sorry 18
6 0
2 years ago
250$ is invested at a bank that pays7% interest.Calculate the amount of money in the account after 1 year, 3 years, 7 years, 20
Vesna [10]

One year = $267.50

Three Years = $302.50

Seven Years = $372.50

Twenty Years = $600.00

Hope this Helps!

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7 0
3 years ago
(1 point) solve the separable differential equation y′(x)=2y(x)+18−−−−−−−−−√, y′(x)=2y(x)+18, and find the particular solution s
luda_lava [24]
We write the equation in terms of dy/dx,
<span>y'(x)=sqrt (2y(x)+18)</span>
dy/dx = sqrt(2y + 18)
dy/dx = sqrt(2) ( sqrt(y + 9)) 

Separating the variables in the equation, we will have:
<span>1/sqrt(y + 9) dy= sqrt(2) dx </span>

Integrating both sides, we will obtain
<span>2sqrt(y+9) = x(sqrt(2)) + c </span>
<span>where c is a constant and can be determined by using the boundary condition given </span>
<span>y(5)=9 : x = 5, y = 9
</span><span>sqrt(9+9) = 5/sqrt(2) + C </span>

<span>C = sqrt(18) - 5/sqrt(2) = sqrt(2) / 2</span>

Substituting to the original equation,
sqrt(y+9) = x/sqrt(2) + sqrt(2) / 2

<span>sqrt(y+9) = (2x + 2) / 2sqrt(2) 
</span>
Squaring both sides, we will obtain,
<span>y + 9 = ((2x+2)^2) / 8</span>

y = ((2x+2)^2) / 8 - 9
7 0
3 years ago
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