1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Pie
3 years ago
11

Can somebody solve this question for me it would be so helpful I will give brainliest first it needs to be rounded to the neares

t 10th

Mathematics
1 answer:
SpyIntel [72]3 years ago
3 0

Answer:

F. 824.8 ft³

Step-by-step explanation:

To find the volume of a cube, you want to multiply the length by width by height.

l = 8.2

w = 9.4

h = 10.7

l • w • h

8.2  • 9.4 • 10.7

= 824.756

Round to the nearest tenth.

824.8 ft³

Hope this helps!

You might be interested in
Jarred wants to buy a go-cart for $1,200. His part-time job pays him $160 a week. He has already saved $400. Which inequality re
Oduvanchick [21]
The answer is B I believe!
8 0
3 years ago
Read 2 more answers
What is the magnitude (size) of 6.8?
lidiya [134]

Answer:

C. 6.8, because |6.8|= 6.8

Step-by-step explanation:

The magnitude of a directed number is a property that turns the number to a positive of its value. Thus, the magnitude of a negative number equals its positive value. Examples:

Find the magnitude of the following numbers:

i. -20

ii. 10

iii. -5

iv. 2

The magnitudes of the numbers can be expressed as:

i. |-20| = 20

ii. |10| = 10

iii. |-5| = 5

iv. |2| = 2

Therefore, the magnitude of 6.8 = 6.8, because |6.8|= 6.8.

7 0
3 years ago
-2.6f + 0.8f - 15 - 4<br><br> help ??
joja [24]

Answer:

= -1.8f-19

Step-by-step explanation:

- Add the similar elements which would give you -1.8f-15-4

- Then subtract -15-4 which gives you -19

7 0
3 years ago
Read 2 more answers
Please do a and b and explain
Blizzard [7]

This is a decay problem,

The equation is written as start value x (1 - rate)^tike

Using the information given in the problem:

a) Total = 120(1-0.12)^Hours

b) Replace hours with 19 and solve:

Total = 120(1-0.12)^19

Total = 120(0.88)^19

Total = 10.57674 mg

Round the answer as needed.

4 0
3 years ago
When integrating polar coordinates, when should one use the polar differential element, <img src="https://tex.z-dn.net/?f=rdrd%2
vitfil [10]
To answer your first question: Whenever you convert from rectangular to polar coordinates, the differential element will *always* change according to

\mathrm dA=\mathrm dx\,\mathrm dy\implies\mathrm dA=r\,\mathrm dr\,\mathrm d\theta

The key concept here is the "Jacobian determinant". More on that in a moment.

To answer your second question: You probably need to get a grasp of what the Jacobian is before you can tackle a surface integral.

It's a structure that basically captures information about all the possible partial derivatives of a multivariate function. So if \mathbf f(\mathbf x)=(f_1(x_1,\ldots,x_n),\ldots,f_m(x_1,\ldots,x_n)), then the Jacobian matrix \mathbf J of \mathbf f is defined as

\mathbf J=\begin{bmatrix}\mathbf f_{x_1}&\cdots&\mathbf f_{x_n}\end{bmatrix}=\begin{bmatrix}{f_1}_{x_1}&\cdots&{f_m}_{x_n}\\\vdots&\ddots&\vdots\\{f_m}_{x_1}&\cdots&{f_m}_{x_n}\end{bmatrix}

(it could be useful to remember the order of the entries as having each row make up the gradient of each component f_i)

Think about how you employ change of variables when integrating a univariate function:

\displaystyle\int2xe^{x^2}\,\mathrm dr=\int e^{x^2}\,\mathrm d(x^2)\stackrel{y=x^2}=\int e^y\,\mathrm dy=e^{r^2}+C

Not only do you change the variable itself, but you also have to account for the change in the differential element. We have to express the original variable, x, in terms of a new variable, y=y(x).

In two dimensions, we would like to express two variables, say x,y, each as functions of two new variables; in polar coordinates, we would typically use r,\theta so that x=x(r,\theta),y=y(r,\theta), and

\begin{cases}x(r,\theta)=r\cos\theta\\y(r,\theta)=r\sin\theta\end{cases}

The Jacobian matrix in this scenario is then

\mathbf J=\begin{bmatrix}x_r&y_\theta\\y_r&y_\theta\end{bmatrix}=\begin{bmatrix}\cos\theta&-r\sin\theta\\\sin\theta&r\cos\theta\end{bmatrix}

which by itself doesn't help in integrating a multivariate function, since a matrix isn't scalar. We instead resort to the absolute value of its determinant. We know that the absolute value of the determinant of a square matrix is the n-dimensional volume of the parallelepiped spanned by the matrix's n column vectors.

For the Jacobian, the absolute value of its determinant contains information about how much a set \mathbf f(S)\subset\mathbb R^m - which is the "value" of a set S\subset\mathbb R^n subject to the function \mathbf f - "shrinks" or "expands" in n-dimensional volume.

Here we would have

\left|\det\mathbf J\right|=\left|\det\begin{bmatrix}\cos\theta&-r\sin\theta\\\sin\theta&r\cos\theta\end{bmatrix}\right|=|r|

In polar coordinates, we use the convention that r\ge0 so that |r|=r. To summarize, we have to use the Jacobian to get an appropriate account of what happens to the differential element after changing multiple variables simultaneously (converting from one coordinate system to another). This is why

\mathrm dx\,\mathrm dy=r\,\mathrm dr\,\mathrm d\theta

when integrating some two-dimensional region in the x,y-plane.

Surface integrals are a bit more complicated. The integration region is no longer flat, but we can approximate it by breaking it up into little rectangles that are flat, then use the limiting process and add them all up to get the area of the surface. Since each sub-region is two-dimensional, we need to be able to parameterize the entire region using a set of coordinates.

If we want to find the area of z=f(x,y) over a region \mathcal S - a region described by points (x,y,z) - by expressing it as the identical region \mathcal T defined by points (u,v). This is done with

\mathbf f(x,y,z)=\mathbf f(x(u,v),y(u,v),z(u,v))

with u,v taking on values as needed to cover all of \mathcal S. The Jacobian for this transformation would be

\mathbf J=\begin{bmatrix}x_u&x_v\\y_u&y_v\\z_u&z_v\end{bmatrix}

but since the matrix isn't square, we can't take a determinant. However, recalling that the magnitude of the cross product of two vectors gives the area of the parallelogram spanned by them, we can take the absolute value of the cross product of the columns of this matrix to find out the areas of each sub-region, then add them. You can think of this result as the equivalent of the Jacobian determinant but for surface integrals. Then the area of this surface would be

\displaystyle\iint_{\mathcal S}\mathrm dS=\iint_{\mathcal T}\|\mathbf f_u\times\mathbf f_v\|\,\mathrm du\,\mathrm dv

The takeaway here is that the procedures for computing the volume integral as opposed to the surface integral are similar but *not* identical. Hopefully you found this helpful.
5 0
3 years ago
Other questions:
  • 50 is 20% of what number
    14·1 answer
  • Need help finding BD
    14·2 answers
  • The sum measures of angle X and angle Y is 90. If the angle X is 30 less than twice the measure of angle Y, what is the measure
    11·1 answer
  • WILL MARK AS BRAINIEST!!!!!!! In this triangle, which of the following is true?
    8·2 answers
  • A bike rental stand at the beach charges $5 to rent a bike in targit charges to every half hour it is rented if someone pays $17
    9·1 answer
  • Subtracting integers by adding opposite
    8·1 answer
  • Y= - 5/3x+3<br> y=1/3x-3
    15·1 answer
  • When the common ratio is greater than 1, the values in the sequence
    6·1 answer
  • An isosceles triangular prism has a triangular end with a base
    7·1 answer
  • Write the absolute value equations in the form |x-b|=c (where b is a number and c can be either number or an expression) that ha
    13·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!