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gladu [14]
3 years ago
8

Need help asap and i will report any unnecessary comments

Mathematics
2 answers:
Flura [38]3 years ago
6 0
191 1/2 divide 1425 by 30 and you get 191 1/2
Inessa [10]3 years ago
5 0

Firstly, divide 30 by 1425

Then, 1425/30 = 47.5

A Mixed number = A whole number + fraction

Your final answer = 47 1/2 trains

Hope this helps <3 Good luck with future exams!

P.S Fun Fact~~ The Mona Lisa has no eyebrows!

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Help asap i will brainlist
aniked [119]

Answer:

8-3n

The way you know is 8 is the hidden word....

in there and it say 3 times   nathans...

So you will take n and times it bye 3..

by doing 3n so 8-3n is your anwser...

<h2>Pwease Mark me Brainliest TY OwO</h2>

3 0
3 years ago
Factor completely x3 – 8
Travka [436]

Answer: (x-2) (x^2 + 2x + 4)

Step-by-step explanation:

x^3 - 8

x^3 - 2^3

(x-2) * (x^2+x * 2 + 2^2)

(x-2) (x^2 + 2x + 4)

3 0
4 years ago
Help me with this ;-;
uysha [10]
If you multiply all the square inches, you would get 15,015
4 0
3 years ago
Find the inverse Laplace transform f(t) of the function F(s). Write uc for the Heaviside function that turns on at c, not uc(t).
zzz [600]

Answer:

F(t)=\frac{-1}{2}e^{7(t-7)}+\frac{1}{2}e^{-7(t-7)}

Step-by-step explanation:

We have given F(S)=\frac{7e^{-7s}}{s^2-49}

Now  F(S)=e^{-7s}G(s)

Here G(S)=\frac{7}{S^2-49}

Now first find the Laplace inverse of G(S)

Using partial fraction

\frac{7}{(s+7)(s-7)}=\frac{A}{(S+7)}+\frac{B}{S-7}

7=A(S-7)+B(S+7)

On comparing the coefficient

A=\frac{1}{2}  and B=\frac{-1}{2}  

On putting the value of A and B  

G(S)=\frac{-1}{2(S+7)}+\frac{1}{2(S+7)}

Taking inverse Laplace

G(t)=\frac{-1}{2}e^{7t}+\frac{1}{2}e^{-7t}

Now in G(s) there is onether term e^{-7s}

So F(t)=\frac{-1}{2}e^{7(t-7)}+\frac{1}{2}e^{-7(t-7)}

6 0
3 years ago
What is the correct factorization of x^2 - 2x - 15?
iragen [17]

Answer:

option b

Step-by-step explanation:

{x}^{2}  - 2x - 15

{x}^{2}  - 5x + 3x - 15 = 0

x(x - 5) + 3(x - 5) = 0

(x - 5)(x + 3) = 0

x = -3 (Not possible)

x = 5

So, x = 5

8 0
3 years ago
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