A <em>scale factor </em>essentially takes all of the lengths on an object and multiplies them by itself.
For instance, a square with side lengths of 4 scaled by a factor of 2 would have scaled side lengths of 4 x 2 = 8, and that same square scaled by a factor of 1/2 would have side lengths 4 x 1/2 = 2. Scaling something by a factor of 1 keeps it exactly the same, since any number multiplied by 1 is unchanged - this means that 1 is basically the "pivot number" for scaling.
Any scale factor <em>greater </em>than one will scale an object <em>up </em>to larger dimensions, while any scale factor <em>less </em>than one will scale an object <em>down </em>to smaller dimensions.
Answer:
x = 4
Step-by-step explanation:
6(6 + x) = 5(5 + x + 3) => secant secant theorem
36 + 6x = 5(8 + x)
36 + 6x = 40 + 5x
Subtract 36 from each side
36 + 6x - 36 = 40 + 5x - 36
6x = 4 + 5x
Subtract 5x from each side
6x - 5x = 4 + 5x - 5x
x = 4
It is 6 was not multiplied by 3
The answer should be 6(m+3)= 6m+ 18
What is asked here is that you isolate y so that the equation takes the form of y = ..., where ... will be something that contains a, b and c but not y. So how do we get there? By applying some standard permutations to equations like so:
aby - b = c
First, we bring the -b term to the right hand side by adding b left and right:
aby -b+b = c+b
The -b and +b cancel out, so we get:
aby = c + b
Then, we divide left and right hand side by ab:
aby/ab = (c+b)/ab
Again, the ab/ab on the left cancels out (it is 1), so we get:
y = (c+b)/ab
And we're done!
So you have to know that it is allowed to add or subtract something (anything) to/from the left and right hand side of an equation. Likewise, you have to know that it is allowed to multiply or divide by something, as long as it isn't 0.
5x - 3x + 4 = -4 +20
2x + 4 + 16
subtract 4 from each side
2x=12
divide each side by 2
x=6
