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Ghella [55]
2 years ago
13

Find the value of x and y that maximize or minimize the objective function.

Mathematics
1 answer:
kogti [31]2 years ago
3 0
0 > x > 2 and y < 8 - x
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If triangle DEF is an isosceles triangle with DE is congruent to EF, find x and the measure of each side
Rudik [331]

Step-by-step explanation:

Given that,

DE = 8x - 13

EF = 5x + 17

DF = x + 21

Also,

DE = EF

which means that,

8x - 13 = 5x + 17

8x - 5x = 17 + 13

3x = 30

x = 30/3

x = 10

Now,

DE = 8x - 13 = 8×10 - 13 = 80 - 13 = 67cm

EF = 5x + 17 = 5×10 + 17 = 50 + 17 = 67cm

DF = x + 21 = 10 + 21 = 31cm

3 0
2 years ago
A student solving for the acceleration of an object has applied appropriate physics principles and obtained the expression a=a1+
egoroff_w [7]

Answer:

a=\frac{3\times 7}{7}+\frac{12}{7}  (First step for obtaining a common denominator for the two fraction)

a=\frac{33}{7}\text{ m/s}^2

Step-by-step explanation:

\text{Given Expression: }a=a_1+\frac{F}{m}

where,

a is acceleration of an object.(Need to calculate)

a_1=3.00\text{ m/s}^2

F=12.0\text{ Kg.m/s}^2

m=7.00\text{ kg}

\text{Substitute }a_1, \text{ F, and m into expression and we get}

a=3+\frac{12}{7}

Now we will simplify above expression for a

First we make common denominator.

Common denominator is 7. So, we make both denominator 7. We multiply by 7 at top and bottom with 3. We get

a=\frac{3\times 7}{7}+\frac{12}{7}  (First step for obtaining a common denominator for the two fraction)

Now we combine the numerator

a=\frac{21+12}{7}

a=\frac{33}{7}\text{ m/s}^2



3 0
3 years ago
Read 2 more answers
Please help . I’ll mark you as brainliest if correct
Oxana [17]

Answer:

30m

Step-by-step explanation:

51-21=30 that is the length of the long piece

8 0
2 years ago
Which of the following is a pair of vertical angles? *
erastovalidia [21]

Answer:

1 and 3, 2 and 4, 5 and 7, and 8 and 65

Step-by-step explanation:

Vertical Angles Congruence Theorem

6 0
2 years ago
Tori went to the eye doctor. He dilated her pupils to twice their normal size during the exam. If her pupils were 2 mm oeiginall
jok3333 [9.3K]
4 pupils bc 2*2=4..................................................................................................................................................................................................................................................................
6 0
2 years ago
Read 2 more answers
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