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3 years ago

Y-axis

Mathematics

1 answer:

butalik [34]3 years ago

5 0

Answer:

2+-7x2-30=2+

Step-by-step explanation:

had a tutor work it out

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Mathematics mh hhhhh

crimeas [40]

Answer:

A. x≥4 ( red on 4)

B. x≤4 ( red on 4)

C. x>4 (blue on 4)

D. x<4 (blue on 4)

Step-by-step explanation:

illustrated

A. x≥4 ( red on 4)

B. x≤4 ( red on 4)

C. x>4 (blue on 4)

D. x<4 (blue on 4)

4 0

3 years ago

Read 2 more answers

A recipe for cookies needs 240g of flour to make enough cookies for 5 people. How much flour would you need to make cookies for

Serga [27]

Answer:

720g

Step-by-step explanation:

5 people = 240g

×3 x3

15 people = 720g

5 0

3 years ago

You have 1240 acres of land, and each acre is worth $52. How much is your land worth in total?

murzikaleks [220]

If one acre is $52, you would multiply 1240 by 52. Your land in total is worth $64,480.

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3 years ago

Find the 2th term of the expansion of (a-b)^4.

vladimir1956 [14]

The second term of the expansion is $-4a^3b$ .

Solution:

Given expression:

$(a-b)^4$

To find the second term of the expansion.

$(a-b)^4$

Using Binomial theorem,

$(a+b)^{n}=\sum_{i=0}^{n}\left(\begin{array}{l}n \\i\end{array}\right) a^{(n-i)} b^{i}$

Here, a = a and b = –b

$$(a-b)^4=\sum_{i=0}^{4}\left(\begin{array}{l}4 \\i\end{array}\right) a^{(4-i)}(-b)^{i}$

Substitute i = 0, we get

$$\frac{4 !}{0 !(4-0) !} a^{4}(-b)^{0}=1 \cdot \frac{4 !}{0 !(4-0) !} a^{4}=a^4$

Substitute i = 1, we get

$$\frac{4 !}{1 !(4-1) !} a^{3}(-b)^{1}=\frac{4 !}{3!} a^{3}(-b)=-4 a^{3} b$

Substitute i = 2, we get

$$\frac{4 !}{2 !(4-2) !} a^{2}(-b)^{2}=\frac{12}{2 !} a^{2}(-b)^{2}=6 a^{2} b^{2}$

Substitute i = 3, we get

$$\frac{4 !}{3 !(4-3) !} a^{1}(-b)^{3}=\frac{4}{1 !} a(-b)^{3}=-4 a b^{3}$

Substitute i = 4, we get

$$\frac{4 !}{4 !(4-4) !} a^{0}(-b)^{4}=1 \cdot \frac{(-b)^{4}}{(4-4) !}=b^{4}$

Therefore,

$$(a-b)^4=\sum_{i=0}^{4}\left(\begin{array}{l}4 \\i\end{array}\right) a^{(4-i)}(-b)^{i}$

$=\frac{4 !}{0 !(4-0) !} a^{4}(-b)^{0}+\frac{4 !}{1 !(4-1) !} a^{3}(-b)^{1}+\frac{4 !}{2 !(4-2) !} a^{2}(-b)^{2}+\frac{4 !}{3 !(4-3) !} a^{1}(-b)^{3}+\frac{4 !}{4 !(4-4) !} a^{0}(-b)^{4}$ $=a^{4}-4 a^{3} b+6 a^{2} b^{2}-4 a b^{3}+b^{4}$

Hence the second term of the expansion is $-4a^3b$ .

3 0

3 years ago

WILL GIVE A BRAINLEST AND 20PTS!! FOR CORRECT ANSWER

Anna007 [38]

Take the conversion of the 1 European Euro and multiply it by 250. That's his total. $342.175. Now take conversion and multiply it by 150. It comes out as $205.305. Lastly, to get what you have left, you need to subtract the full amount by the amount you spent. Which leaves you at,

$136.87

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3 years ago